將負秒轉換爲小時：分：秒

Question

我想創建一個構造函數，它需要幾秒鐘時間並將其轉換爲HH：MM：SS。我可以很容易地做到這一點，積極秒，但我遇到了一些困難與負秒。

這是我到目前爲止有：

private final int HOUR, MINUTE, SECOND, TOTAL_TIME_IN_SECONDS; 

public MyTime(int timeInSeconds) { 
    if (timeInSeconds < 0) { 
     //Convert negative seconds to HH:MM:SS 
    } else { 
     this.HOUR = (timeInSeconds/3600) % 24; 
     this.MINUTE = (timeInSeconds % 3600)/60; 
     this.SECOND = timeInSeconds % 60; 
     this.TOTAL_TIME_IN_SECONDS 
       = (this.HOUR * 3600) 
       + (this.MINUTE * 60) 
       + (this.SECOND); 
    } 
} 

如果TimeInSeconds是-1我想要的時候返回23:59:59等

謝謝！

Answer 1

如何

if (timeInSeconds < 0) { 
    return MyTime(24 * 60 * 60 + timeInSeconds); 
} 

因此它會循環，你將利用現有的邏輯。

，可隨時更換if與while循環，以避免遞歸

Answer 2

if (time < 0) 
    time += 24 * 60 * 60; 

是添加到構造函數的開始。 雖然如果你期望有大的負數，那麼IF就會被放棄。

Answer 3

class MyTime { 
    private final int HOUR, MINUTE, SECOND, TOTAL_TIME_IN_SECONDS; 
    private static final int SECONDS_IN_A_DAY = 86400; 

    public MyTime(int timeInSeconds) { 
    prepare(normalizeSeconds(timeInSeconds)); 
    } 

    private int normalizeSeconds(int timeInSeconds) { 
     //add timeInSeconds % SECONDS_IN_A_DAY modulo operation if you expect values exceeding SECONDS_IN_A_DAY: 
     //or throw an IllegalArgumentException 
     if (timeInSeconds < 0) { 
     return SECONDS_IN_A_DAY + timeInSeconds; 
    } else { 
     return timeInSeconds; 
    } 
    } 

    private prepare(int timeInSeconds) { 
     this.HOUR = (timeInSeconds/3600) % 24; 
     this.MINUTE = (timeInSeconds % 3600)/60; 
     this.SECOND = timeInSeconds % 60; 
     this.TOTAL_TIME_IN_SECONDS 
       = (this.HOUR * 3600) 
       + (this.MINUTE * 60) 
       + (this.SECOND); 
    } 

}