在Ruby中

解析複雜的網址，我想在這個網址檢索「Q」的價值：在Ruby中

http://www.google.com/url?sa=X&q=http://nashville.broadwayworld.com/article/Just_in_time_for_Halloween_Circle_Players_does_JEKYLL_HYDE_20101013&ct=ga&cad=:s7:f1:v1:d2:i0:lt:e0:p0:t1286988171:&cd=yQoOdKUFTLo&usg=AFQjCNEg2inHF8hXGEvG-TxMQyMx7YGHkA

，如果我用這個：

uri = URI.parse("http://www.google.com/url?sa=X&q=http://nashville.broadwayworld.com/article/Just_in_time_for_Halloween_Circle_Players_does_JEKYLL_HYDE_20101013&ct=ga&cad=:s7:f1:v1:d2:i0:lt:e0:p0:t1286988171:&cd=yQoOdKUFTLo&usg=AFQjCNEg2inHF8hXGEvG-TxMQyMx7YGHkA") 

uri_params = CGI.parse(uri.query) 

uri_params['q']

我收到此錯誤：

URI::InvalidURIError: bad URI(is not URI?)

謝謝！

來源

2010-10-13 Bob Brodie

正如傑德施耐德指出工作。你發佈的確切例子在irb中有效。我懷疑的是，你可能以這種或那種方式將輸入URI.parse作爲用戶的參數。我有一個使用Sinatra的類似問題，必須在使用URL.parse之前通過CGI :: unescape傳遞url字符串。 – maz 2010-10-13 20:21:59

似乎爲我

ruby-1.8.7-p249 > require 'uri' 
=> true 
ruby-1.8.7-p249 > require 'cgi' 
=> true 
ruby-1.8.7-p249 > uri = URI.parse("http://www.google.com/url?sa=X&q=http://nashville.broadwayworld.com/article/Just_in_time_for_Halloween_Circle_Players_does_JEKYLL_HYDE_20101013&ct=ga&cad=:s7:f1:v1:d2:i0:lt:e0:p0:t1286988171:&cd=yQoOdKUFTLo&usg=AFQjCNEg2inHF8hXGEvG-TxMQyMx7YGHkA") 
=> #<URI::HTTP:0x10127b288 URL:http://www.google.com/url?sa=X&q=http://nashville.broadwayworld.com/article/Just_in_time_for_Halloween_Circle_Players_does_JEKYLL_HYDE_20101013&ct=ga&cad=:s7:f1:v1:d2:i0:lt:e0:p0:t1286988171:&cd=yQoOdKUFTLo&usg=AFQjCNEg2inHF8hXGEvG-TxMQyMx7YGHkA> 
ruby-1.8.7-p249 > uri_params = CGI.parse(uri.query) 
=> {"cd"=>["yQoOdKUFTLo"], "sa"=>["X"], "cad"=>[":s7:f1:v1:d2:i0:lt:e0:p0:t1286988171:"], "ct"=>["ga"], "q"=>["http://nashville.broadwayworld.com/article/Just_in_time_for_Halloween_Circle_Players_does_JEKYLL_HYDE_20101013"], "usg"=>["AFQjCNEg2inHF8hXGEvG-TxMQyMx7YGHkA"]} 
ruby-1.8.7-p249 > uri_params['q'] 
=> ["http://nashville.broadwayworld.com/article/Just_in_time_for_Halloween_Circle_Players_does_JEKYLL_HYDE_20101013"]

來源

2010-10-13 20:02:01

回答

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