在樂譜呼叫中添加列表名稱作爲劇情標題R

sample <- 
structure(list(GB05 = structure(c(22L, 34L, 26L, 2L), .Dim = 4L, .Dimnames = structure(list(
    c("98", "100", "102", "106")), .Names = ""), class = "table"), 
    GB18 = structure(c(8L, 14L, 70L), .Dim = 3L, .Dimnames = structure(list(
     c("173", "175", "177")), .Names = ""), class = "table"), 
    GB06 = structure(c(2L, 16L, 48L, 10L, 10L, 6L), .Dim = 6L, .Dimnames = structure(list(
     c("234", "238", "240", "242", "244", "246")), .Names = ""), class = "table"), 
    GB27 = structure(c(2L, 28L, 2L, 2L, 4L, 3L, 2L, 2L, 15L, 
    17L, 4L, 5L), .Dim = 12L, .Dimnames = structure(list(c("145", 
    "147", "149", "151", "156", "159", "165", "167", "169", "171", 
    "173", "175")), .Names = ""), class = "table"), GB24 = structure(c(2L, 
    4L, 41L, 10L, 6L, 2L, 14L, 2L, 3L), .Dim = 9L, .Dimnames = structure(list(
     c("240", "241", "242", "243", "244", "247", "249", "251", 
     "253")), .Names = ""), class = "table"), GB28 = structure(c(30L, 
    22L, 2L, 10L, 2L, 4L, 2L, 2L, 2L), .Dim = 9L, .Dimnames = structure(list(
     c("363", "364", "365", "367", "371", "377", "380", "384", 
     "390")), .Names = ""), class = "table"), GB15 = structure(c(12L, 
    16L, 43L, 2L, 3L, 4L), .Dim = 6L, .Dimnames = structure(list(
     c("142", "144", "146", "147", "148", "152")), .Names = ""), class = "table"), 
    GB02 = structure(c(6L, 78L, 4L), .Dim = 3L, .Dimnames = structure(list(
     c("194", "197", "200")), .Names = ""), class = "table"), 
    GB10 = structure(c(2L, 36L, 7L, 1L, 16L, 20L), .Dim = 6L, .Dimnames = structure(list(
     c("124", "126", "128", "130", "132", "134")), .Names = ""), class = "table"), 
    GB14 = structure(c(3L, 6L, 7L, 37L, 7L), .Dim = 5L, .Dimnames = structure(list(
     c("181", "184", "187", "193", "196")), .Names = ""), class = "table")), .Names = c("GB05", 
"GB18", "GB06", "GB27", "GB24", "GB28", "GB15", "GB02", "GB10", 
"GB14"))

如何在此列表中顯示名稱以作爲劇情標題在這個低呼叫（每個劇情一個標題）？在樂譜呼叫中添加列表名稱作爲劇情標題R

dev.new() 
par(mfrow=c(2,5)) 
lapply(sample,function(x) plot(x,main=names[x]))

我不明白爲什麼main = names [x]不起作用。

來源

2013-02-09 Chargaff

您的'dput'輸出未正確複製/粘貼。嘗試複製時會出現錯誤。 – Arun 2013-02-09 16:58:49

@Arun更正，謝謝你指出這一點。 – Chargaff 2013-02-09 17:03:31

@Chargaff，不。 *現在*它是固定的。你的第一行讀取'sample <--dput（afn）'。你不需要包含'dput（afn）'部分。 – A5C1D2H2I1M1N2O1R2T1 2013-02-09 17:07:28

在列表項的名稱，而不是使用lapply：

lapply(names(afn), function(x) plot(afn[[x]], main=x))

enter image description here

要查看爲什麼你沒有得到你的名字，運行lapply(afn, function(x) names(x))給你名各列表項或其他東西。嘗試與lapply(names(afn), function(x) x)相同並比較差異。然後，請記住，我們可以使用[[按名稱提取單個列表項。

來源

2013-02-09 16:52:55 A5C1D2H2I1M1N2O1R2T1

我會在這裏使用'sapply'來訪問使用$ name_plot ... – agstudy 2013-02-09 19:30:17

在樂譜呼叫中添加列表名稱作爲劇情標題R

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