附加字符串

Question

我知道這對於某人來說很容易。我需要組合對象來創建一個地址。我不知道該怎麼做。我想...

NSString *agcstr = [infoDictionary objectForKey:@"physstr"]; 
NSString *agccity = [infoDictionary objectForKey:@"physcity"]; 
NSString *agcstate = [infoDictionary objectForKey:@"physstate"]; 
NSString *agczip = [infoDictionary objectForKey:@"physzip"]; 

dvController.agcaddress = [agcstr stringByAppendingString:@"\n"  stringByAppendingString:agccity stringByAppendingString:@", " stringByAppendingString:agczip]; 

這是完全錯誤的，但我總是至少嘗試的東西:)

Answer 1

請嘗試以下方法：

NSString *agcstr = [infoDictionary objectForKey:@"physstr"]; 
NSString *agccity = [infoDictionary objectForKey:@"physcity"]; 
NSString *agcstate = [infoDictionary objectForKey:@"physstate"]; 
NSString *agczip = [infoDictionary objectForKey:@"physzip"]; 

dvController.agcaddress = [[[[agcstr stringByAppendingString:@"\n"] stringByAppendingString:agccity] stringByAppendingString:@", "] stringByAppendingString:agczip]; 

另外，

dvController.agcaddress = [NSString stringWithFormat:@"%@ \n %@, %@", agcstr, agccity, agczip]; 

Answer 2

嘗試stringWithFormat

dvController.agcaddress = [NSString stringWithFormat:@"%@, %@, %@, %@", agcstr, agccity, agcstate, agczip];