我想循環這3個圖像,其次是他們的ul和李。一旦點擊,我發現事件處理程序沒有在第一個以外的任何圖像上進行偵聽。請幫助我。for循環4 DOM元素和他們的事件在JS
JS
var main = function() {
var recipeArray = ['drink', 'firstCourse', 'mainDish', 'dessert'];
var recipeArrayLength = recipeArray.length;
for (var i = 0; i < recipeArrayLength; i++) {
var $checkBoxes = document.createElement('div');
$checkBoxes.setAttribute("class", "checkBoxes");
var $recipePicContainer = document.createElement('span');
$recipePicContainer.setAttribute("class", "recipePicContainer");
function makeRecipePic() {
var recipe = document.createElement("IMG");
recipe.setAttribute("src", "../images/grasshopper-cocktail.jpg");
recipe.setAttribute("class", "recipe");
$recipePicContainer.appendChild(recipe);
}
makeRecipePic();
var mainContainer = document.getElementsByClassName('mainContainer');
mainContainer[0].appendChild($checkBoxes);
var $div = document.createElement('div');
$div.innerHTML = 'CockTails';
$recipePicContainer.appendChild($div);
$checkBoxes.appendChild($recipePicContainer);
var $recipes = document.createElement("ul");
var $checkboxes = document.getElementsByClassName('checkBoxes');
var x = document.createElement("INPUT");
x.setAttribute("type", "checkbox");
}
for (var j = 1; j <= 6; j++) {
var li = document.createElement("li");
li.className = "ingredients";
li.setAttribute("type", "checkbox");
var a = document.createElement("a");
a.innerHTML = "Ingredient " + j;
li.appendChild(a);
$recipes.appendChild(li);
}
var b = document.createElement("li");
li.innerHTML = "Lorem ipsum dolor sit amet, consectetur adipiscing elit.";
li.className = "Instructions";
$checkboxes[0].appendChild($recipes);
$('.recipes').hide();
$('<input type="checkbox" value="1" />').prependTo(".ingredients");
$('.mainContainer .recipePicContainer').click(function() {
$(this).next('ul').toggle("slow").toggleClass('selected');
});
};
$(document).ready(main);
您的事件處理程序在每個圖像上單擊事件偵聽,您的內部邏輯錯誤,把console.log()或警報點擊處理函數 –
嘿@Nitin,我會試試thanx! –