4
[0,0,1,1,1,0,0,0,1,1,0,0,1,1,1,1]
名單,我想將它們分組,然後找到每個組的長度。因此,其結果將是這樣的:
[[2,0],[3,1].....[4,1]]
[0,0,1,1,1,0,0,0,1,1,0,0,1,1,1,1]
名單,我想將它們分組,然後找到每個組的長度。因此,其結果將是這樣的:
[[2,0],[3,1].....[4,1]]
>>> import itertools
>>> l = [0,0,1,1,1,0,0,0,1,1,0,0,1,1,1,1]
>>> [(len(list(g)), k) for k,g in itertools.groupby(l)]
[(2, 0), (3, 1), (3, 0), (2, 1), (2, 0), (4, 1)]
In [7]: import itertools
In [8]: [[sum(1 for _ in g),v] for v,g in itertools.groupby(l)]
Out[8]: [[2, 0], [3, 1], [3, 0], [2, 1], [2, 0], [4, 1]]
哪裏l
是您的輸入列表中。
您也可以使用[funcy](https://github.com/Suor/funcy)庫中的[ilen](http://funcy.readthedocs.org/en/latest/seqs.html#ilen) len(list(...))'的速度。 – Suor