甲骨文四捨五入問題

Question

我使用此代碼的十進制值向下取整到25 即一個倍數，如果值是33.60它應該輪33.50

create or replace 
PROCEDURE   "TEST1" (PQUERY IN VARCHAR2) as 
prNspValue number(14,2) :=''; 
p_percentage_Value number(4,2) :=''; 
    begin 
    prNspValue:=33.60; 
    dbms_output.put_line(prNspValue); 
    p_percentage_Value:=substr(prNspValue,instr(prNspValue,'.')+1,length(prNspValue)); 
    dbms_output.put_line(p_percentage_value); 
    p_percentage_Value:=p_percentage_Value-mod(p_percentage_Value,25); 
    dbms_output.put_line(p_percentage_value); 
    if(p_percentage_Value!=0)then 
    prNspValue:=substr(prNspValue,1,instr(prNspValue,'.'))+p_percentage_Value/100; 
    else 
    prNspValue:=substr(prNspValue,1,instr(prNspValue,'.')); 
    end if; 
dbms_output.put_line(prNspValue);  
end; 

，但問題是當值33.60取爲33.6。所以它正在四捨五入到33.0。 我該如何糾正這段代碼？

Answer 1

，你可以直接使用FLOOR(your_number*4)/4輪函數：

SQL> WITH my_data AS (
    2  SELECT 33.00 num FROM dual 
    3  UNION ALL SELECT 33.10 FROM dual 
    4  UNION ALL SELECT 33.20 FROM dual 
    5  UNION ALL SELECT 33.30 FROM dual 
    6  UNION ALL SELECT 33.40 FROM dual 
    7  UNION ALL SELECT 33.50 FROM dual 
    8  UNION ALL SELECT 33.60 FROM dual 
    9  UNION ALL SELECT 33.70 FROM dual 
10  UNION ALL SELECT 33.80 FROM dual 
11  UNION ALL SELECT 33.90 FROM dual 
12 ) SELECT num, 
13   floor (num * 4)/4 rounded 
14  FROM my_data; 

     NUM ROUNDED 
---------- ---------- 
     33   33 
     33,1   33 
     33,2   33 
     33,3  33,25 
     33,4  33,25 
     33,5  33,5 
     33,6  33,5 
     33,7  33,5 
     33,8  33,75 
     33,9  33,75 

10 rows selected