爲什麼使用Spring 1.5.4.RELEASE和Eclipselink 2.6.4進行以下兩個簡單的集成測試失敗?意外的令牌:)findAll和findByKeyIn使用Spring和Eclipselink JPA
@RunWith(SpringRunner.class)
@SpringBootTest(classes = {MyApp.class})
@WebAppConfiguration
@DirtiesContext(classMode = ClassMode.BEFORE_CLASS)
public class DbDummyIT {
@Autowired
private DbDummyRepository repo;
@Test
public void findAllFails() {
List<String> keys = Arrays.asList("1", "2");
List<DbDummy> result = repo.findAll(keys);
assertThat(result.isEmpty()).isTrue();
}
@Test
public void findByKeyInFails() {
List<String> keys = Arrays.asList("1", "2");
List<DbDummy> result = repo.findByKeyIn(keys);
assertThat(result.isEmpty()).isTrue();
}
}
基於:
@Entity
@UuidGenerator(name = DbDummy.KEY_GENERATOR)
public class DbDummy {
public static final String KEY_GENERATOR = "KeyGenerator";
@Id
@Column(name = ColumnName.KEY, nullable = false)
@GeneratedValue(generator = KEY_GENERATOR)
public String key;
}
@Repository
public interface DbDummyRepository extends JpaRepository<DbDummy, String> {
List<DbDummy> findByKeyIn(List<String> keys);
}
兩個測試調用find
查詢時失敗,並JpaSystemException。錯誤信息是:
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.6.4.v20160829-44060b6): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLSyntaxErrorException: unexpected token:) in statement [SELECT Key FROM DBDUMMY WHERE (Key IN ((?,?)))]
Error Code: -5581
Call: SELECT Key FROM DBDUMMY WHERE (Key IN ((?,?)))
bind => [2 parameters bound]
Query: ReadAllQuery(referenceClass=DbDummy sql="SELECT Key FROM DBDUMMY WHERE (Key IN (?))")
該聲明對我來說確實是錯誤的。不是Key IN ((?, ?))
查詢雙值元組列表?不應該查詢字符串列表Key IN (?, ?)
?
用'Collection'給它一個嘗試,(當我在它)'Iterable',但於事無補。我們得到一個JpaSystemException並且它裏面有SQL的事實似乎也證明了Spring *確實識別了用'List'聲明的方法。 – Florian