我使用彈簧mvc。當method = post時,我無法從url獲取參數。但是當我將方法更改爲GET時,我可以獲取所有參數。如何獲得param方法post spring mvc?
這是我的形式:
<form method="POST" action="http://localhost:8080/cms/customer/create_customer" id="frmRegister" name ="frmRegister" enctype="multipart/form-data">
<input class ="iptRegister" type="text" id="txtEmail" name="txtEmail" value="" />
<input class ="iptRegister" type="password" id="txtPassword" name="txtPassword" value="" />
<input class ="iptRegister" type="text" id="txtPhone" name="txtPhone" value="" />
<input type="button" id="btnRegister" name="btnRegister" value="Register" onclick="" style="cursor:pointer"/>
</form>
這是我的控制器:
@RequestMapping(value= "/create_customer", method = RequestMethod.POST)
@ResponseBody
public String createCustomer(HttpServletRequest request,
@RequestParam(value="txtEmail", required=false) String email,
@RequestParam(value="txtPassword", required=false) String password,
@RequestParam(value="txtPhone", required=false) String phone){
ResultDTO<String> rs = new ResultDTO<String>();
rs.setStatus(IConfig.SHOW_RESULT_SUCCESS_ON_MAIN_SCREEN);
try{
Customer c = new Customer();
c.setEmail(email);
c.setPassword(password);
c.setPhone(phone);
customerService.insert(c);
rs.setData("Insert success");
}catch(Exception ex){
log.error(ex);
rs.setStatus(IConfig.SHOW_RESULT_ERROR_ON_MAIN_SCREEN);
rs.setData("Insert failure");
}
return rs.toString();
}
我怎樣才能解決呢?
您如何在JSP中設置這些參數?你能展示更多的代碼嗎? – adarshr