2012-03-29 78 views
0

我想從PostgreSQL數據庫(字段類型是文本)帶有ajax到我的網頁中的一組文本。我遇到的問題是換行符,它在數據庫中沒有換行符時運行良好,但是當我在數據庫中的文本中使用新行時,json不會向我提供它存儲的數據。在json對象中接收換行

function selectCalendarEvents(user_id, event_datestart, event_datestop, callback) { 
    var request; 
    if(window.XMLHttpRequest) 
     request = new XMLHttpRequest(); 
    else 
     request = new ActiveXObject("Microsoft.XMLHTTP"); 

    request.onreadystatechange = function() { 
     if (request.readyState == 4 && request.status == 200) { 
      if(request.responseText.substr(0, 6) == "error ") 
       alert(errorName[request.responseText.substr(6)]); 
      else { 
       jsonCalendarEvents = $.parseJSON(request.responseText); 
       selectEvents(user_id, event_datestart, event_datestop, callback); 
      } 
     } 
    } 
    request.open("GET", "php/calendar.php?action=selectCalendarEvents&user_id=" + user_id + "&event_datestart=" + event_datestart + "&event_datestop=" + event_datestop, true); 
    request.setRequestHeader("If-Modified-Since", "Sat, 1 Jan 2000 00:00:00 GMT"); 
    request.send(); 
} 

這是我的JavaScript函數,它要求數據集

if($action == "selectCalendarEvents") { 
     $user_id = $_GET["user_id"]; 
     $event_datestart = "'" . $_GET["event_datestart"] . "'"; 
     $event_datestop = "'" . $_GET["event_datestop"] . "'"; 

     require_once("connect.php"); 
     $query = "SELECT event_id, event_name, event_datestart, event_datestop, event_timestart, event_timestop, calendar_events.calendar_group, calendar_color, event_info FROM calendar_events LEFT JOIN calendar_calendars ON calendar_events.calendar_group = calendar_calendars.calendar_group WHERE user_id = " . $user_id . " AND calendar_show = true AND event_datestart <= ". $event_datestop . " AND event_datestop >= " . $event_datestart; 
     $result = pg_query($connect, $query); 
     if(!$result) 
      die("error 1"); // query error 

     $comma = ''; 
     $json = '{"events":['; 
     while ($row = pg_fetch_row($result)) { 
      $json .= $comma . '{'; 
      $json .= '"event_id":"' . $row[0] . '",'; 
      $json .= '"event_name":"' . $row[1] . '",'; 
      $json .= '"event_datestart":"' . $row[2] . '",'; 
      $json .= '"event_datestop":"' . $row[3] . '",'; 
      $json .= '"event_timestart":"' . $row[4] . '",'; 
      $json .= '"event_timestop":"' . $row[5] . '",'; 
      $json .= '"calendar_group":"' . $row[6] . '",'; 
      $json .= '"calendar_color":"' . $row[7] . '",'; 
      $json .= '"event_info":"' . $row[8] . '"'; 
      $json .= '}'; 
      $comma = ','; 
     } 
     $json .= ']}'; 

     echo $json; 
    } 

這是我的PHP返回的數據集。如果行[8] aka event_info存儲帶有換行符的文本..當我嘗試用事件填充日曆時,它似乎json不存儲任何數據或smt那樣。

+2

逃生JavaScript中的新行: http://stackoverflow.com/questions/4253367/how-to-escape -a-json-string-containing-newline-characters-using-javascript – bArmageddon 2012-03-29 09:30:12

+0

你也可以閱讀關於替換json [line break到html換行符]的教程(http://www.lampcoder.com/how-to-parse -line-斷裂-使用-jQuery的後方法和 - JSON /) – 2012-08-16 12:05:22

回答

0

我發現我應該用<br/>替換\r\n,它會工作。即時通訊使用這樣replace(/\r\n/g, "<br/>")當我給響應字符串成JSON你parseJSON之前

jsonCalendarEvents = $.parseJSON(request.responseText.replace(/\r\n/g, "<br/>"));