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我有一個網站，我需要把一個聊天框，但是當有人寫的用戶必須刷新整個頁面閱讀文本，但我需要做到這一點自動更新數據請幫幫我。如何更新數據從MySQL數據庫刷新頁面
現在，這是代碼：
<?
session_start();
include("includes/config.php");
if($_GET['with']){
if($_SESSION['login']){
if($_SESSION['login'] == $_GET['with']){
header("Location: index.php");
}else{
$id = $_SESSION['login'];
$with = intval($_GET['with']);
if($_POST['submit']){
$text = $_POST['text'];
if(empty($text)){
}else{
$query = mysqli_query($connect,"INSERT INTO chat(`from`,`to`,`topic`) VALUES('$id','$with','$text')");
}
}
?>
<form method="post" action="chat.php?with=<?=$with?>">
<textarea name="text" placeholder="Write Here..." style="text-align:right;resize:none;width:100%;height:200px;font-size:24">
</textarea>
<br/>
<input type="submit" name="submit" value="Send"/>
</form>
<div id="chat">
<?
$query = mysqli_query($connect,"SELECT * FROM users WHERE id='$id'");
$f = mysqli_fetch_array($query);
$query = mysqli_query($connect,"SELECT * FROM users WHERE id='$with'");
$ff = mysqli_fetch_array($query);
$query = mysqli_query($connect,"SELECT * FROM chat order by id desc");
while($fetch = mysqli_fetch_array($query)){
if($fetch['from'] == $with && $fetch['to'] == $id or $fetch['from'] == $id && $fetch['to'] == $with){
if($fetch['from'] == $f['id']){
echo "<div style='word-wrap: break-word;'>".$f['fname']." ".$f['lname'].":<br/>".$fetch['topic']."</div>";
}
if($fetch['from'] == $ff['id']){
echo "<div style='max-width:200px;word-wrap: break-word;'>".$ff['fname']." ".$ff['lname'].":<br/>".$fetch['topic']."</div>";
}
}
}?>
</div>
<?}
}else{
header("Location: index.php");
}
}else{
header("Location: index.php");
}
>
Ajax，棘輪（Websockets）！使用它們...他們將幫助 – Tushar
您好，我可以編寫一個可以刷新div的代碼嗎？ –
是的，嘗試搜索一下;-) http://stackoverflow.com/questions/17886578/refresh-part-of-page-div –