我有這兩個MySQL
表:打印年月日列表
desc students;
+---------------------------+---------------+
| Field | Type |
+---------------------------+---------------+
| student_id | INT(11) |
| student_firstname | VARCHAR(255) |
| student_lastname | VARCHAR(255) |
+---------------------------+---------------+
desc studentabsence;
+---------------------------+---------------+
| Field | Type |
+---------------------------+---------------+
| student_id | INT(11) |
| student_absence_startdate | date |
| student_absence_enddate | date |
+---------------------------+---------------+
如果我運行下面的查詢:
SELECT
*
FROM
students s
INNER JOIN studentabsence sa
ON s.student_id = sa.student_id
WHERE s.student_id = '1'
我得到以下輸出:
+------------+-------------------+-----------------+------------+---------------------------+-------------------------+
| student_id | student_firstname | student_lastname| student_id | student_absence_startdate | student_absence_enddate |
+------------+-------------------+-----------------+------------+---------------------------+-------------------------+
| 1 | John | Doe | 1 | 2012-08-01 | 2012-08-08 |
+------------+-------------------+-----------------+------------+---------------------------+-------------------------+
現在,我有一個<form>
用戶可以選擇一個stu凹痕和日期範圍。我想知道是否有可能將用戶選擇的兩個日期與數據庫值進行比較,並且如果存在匹配,則回顯學生有數據的該範圍之間的所有工作日。
因此,使用上面的例子中,如果用戶的職位以下形式:
student_id = '1'
student_absence_startdate = '2012-08-02'
student_absence_enddate = '2012-08-06'
我想echo
:
2012-08-02
2012-08-03
2012-08-06
在正確的方向的任何指針被higly理解。
將字段類型從'varchar'更改爲'date'。然後你可以對它進行日期操作 – 2012-08-13 09:50:56