集團通過SQL語句 - 在一行鞏固成果

Question

我創建了一個數據庫表叫tbl_timesheet_hours如下：

timesheet_no 
work_order_no 
work_order_date 
work_order_hours 

與表中填充數據：

timesheet_no work_order_no work_order_date  work_order_hours 
4    NTS0026B  2012-01-02   1 
4    NTS0031B  2012-01-02   9 
4    NTS0031B  2012-01-03   8 
4    NTS0031B  2012-01-04   7 
4    NTS0031B  2012-01-05   6 
4    NTS0031B  2012-01-06   5 
4    NTS0031B  2012-01-07   4 
4    NTS0031B  2012-01-08   3 

我需要創建該查詢將形成時間表報告的基礎，該報告可以以典型的承包商時間表格式打印，即它將顯示第一列中的work_order_no字段，然後顯示每天分配的小時數。我所創建的查詢是：

SELECT 
    work_order_no, 
    switch(Format(work_order_date,'ddd') = "Mon", SUM(work_order_hours)) AS [Mon], 
    switch(Format(work_order_date,'ddd') = "Tue", SUM(work_order_hours)) AS [Tue], 
    switch(Format(work_order_date,'ddd') = "Wed", SUM(work_order_hours)) AS [Wed], 
    switch(Format(work_order_date,'ddd') = "Thu", SUM(work_order_hours)) AS [Thu], 
    switch(Format(work_order_date,'ddd') = "Fri", SUM(work_order_hours)) AS [Fri], 
    switch(Format(work_order_date,'ddd') = "Sat", SUM(work_order_hours)) AS [Sat], 
    switch(Format(work_order_date,'ddd') = "Sun", SUM(work_order_hours)) AS [Sun] 
FROM tbl_timesheet_hours 
WHERE timesheet_no=4 
GROUP BY work_order_date, work_order_no; 

查詢生成以下結果集，

work_order_no Mon Tue Wed Thu Fri Sat Sun 
NTS0026B   1      
NTS0031B   9      
NTS0031B    8     
NTS0031B     7    
NTS0031B      6   
NTS0031B       5  
NTS0031B        4 
NTS0031B         3 

是否有可能重組查詢產生以下結果集？

work_order_no Mon Tue Wed Thu Fri Sat Sun 
NTS0026B  1      
NTS0031B  9 8 7 6 5 4 3 

任何類型的援助將不勝感激。謝謝。

Answer 1

如下您將使用交叉表查詢：

TRANSFORM Sum(tbl_timesheet_hours.[work_order_hours]) AS SumOfwork_order_hours 
SELECT tbl_timesheet_hours.[work_order_no], Sum(tbl_timesheet_hours.[work_order_hours]) AS  [Total Of work_order_hours] 
FROM tbl_timesheet_hours 
GROUP BY tbl_timesheet_hours.[work_order_no] 
ORDER BY Format([work_order_date],'ddd') 
PIVOT Format([work_order_date],'ddd') In ("Mon","Tue","Wed","Thu","Fri","Sat","Sun"); 

Answer 2

您是否嘗試過使用SWITCH表達式裏面SUM()？就像這樣：

SELECT 
    work_order_no, 
    SUM(switch(Format(work_order_date,'ddd') = "Mon", work_order_hours)) AS [Mon], 
    SUM(switch(Format(work_order_date,'ddd') = "Tue", work_order_hours)) AS [Tue], 
    SUM(switch(Format(work_order_date,'ddd') = "Wed", work_order_hours)) AS [Wed], 
    SUM(switch(Format(work_order_date,'ddd') = "Thu", work_order_hours)) AS [Thu], 
    SUM(switch(Format(work_order_date,'ddd') = "Fri", work_order_hours)) AS [Fri], 
    SUM(switch(Format(work_order_date,'ddd') = "Sat", work_order_hours)) AS [Sat], 
    SUM(switch(Format(work_order_date,'ddd') = "Sun", work_order_hours)) AS [Sun] 
FROM tbl_timesheet_hours 
WHERE timesheet_no=4 
GROUP BY work_order_no; 

除此之外，從GROUP BY也work_order_date刪除。