Django的：總的生日每一天接下來的30天內

我有類似的模型，以這樣的：Django的：總的生日每一天接下來的30天內

class Person(models.Model): 
    name = models.CharField(max_length=40) 
    birthday = DateTimeField() # their next birthday

我想獲得總生日每天的列表在未來30天。因此，例如，該列表是這樣的：

[[9, 0], [10, 3], [11, 1], [12, 1], [13, 5], ... #30 entries in list

列表中的每個列表項的日期數字，然後在這一天過生日的數量。例如5月9日有0個生日。

最新通報

我的數據庫是sqlite3的 - 會動在未來的Postgres。

來源

2011-05-09 ErnieP

掛起 - 生日場是他們在*本年*的生日，或他們的實際出生日期？ – 2011-05-09 12:39:15

是的，這將是他們今年的生日。 – ErnieP 2011-05-09 12:44:31

我會得到天的列表和生日指望這樣：

from datetime import date, timedelta  
today = date.today() 
thirty_days = today + timedelta(days=30) 

# get everyone with a birthday 
people = Person.objects.filter(birthday__range=[today, thirty_days]) 

birthday_counts = [] 
for date in [today + timedelta(x) for x in range(30)]: 
    # use filter to get only birthdays on given date's day, use len to get total 
    birthdays = [date.day, len(filter(lambda x: x.birthday.day == date.day, people))] 
    birthday_counts.append(birthdays)

來源

2011-05-09 14:08:44 zeekay

這似乎是個訣竅，非常感謝你!!! – ErnieP 2011-05-09 14:48:13

謝謝，儘管使用'annotate'方法將count和日期結合起來更好。你應該使用[丹尼爾羅斯曼的答案]（http://stackoverflow.com/questions/5936966/django-total-birthdays-each-day-for-the-next-30-days/5937638#5937638），而不是 – zeekay 2011-05-09 15:36:57

但作爲丹尼爾說，他的方法不適用於DateTime，這是我的。 – ErnieP 2011-05-10 05:52:57

事情是這樣的 -

from datetime import date, timedelta 

class Person(models.Model): 
    name = models.CharField(max_length=40) 
    birthday = models.DateField() 

    @staticmethod 
    def upcoming_birthdays(days=30): 
     today = date.today() 
     where = 'DATE_ADD(birthday, INTERVAL (YEAR(NOW()) - YEAR(birthday)) YEAR) BETWEEN DATE(NOW()) AND DATE_ADD(NOW(), INTERVAL %S DAY)' 
     birthdays = Person.objects.extra(where=where, params=[days]).values_list('birthday', flat=True) 
     data = [] 
     for offset in range(0, days): 
      i = 0 
      d = today + timedelta(days=offset) 
      for b in birthdays: 
       if b.day == d.day and b.month == d.month: 
        i += 1 
      data.append((d.day, i)) 
     return data 

print Person.upcoming_birthdays()

來源

2011-05-09 12:57:12 s29

謝謝！這將與sqlite3（我目前的開發數據庫）工作？ – ErnieP 2011-05-09 13:02:00

我想你不需要那個自定義SQL。此外，引用多個對象的函數在Manager上的效果要好於Model – Eduardo 2011-05-09 13:08:00

from django.db.models import Count 
import datetime 
today = datetime.date.today() 
thirty_days = today + datetime.timedelta(days=30) 
birthdays = dict(Person.objects.filter(
        birthday__range=[today, thirty_days] 
       ).values_list('birthday').annotate(Count('birthday'))) 


for day in range(30): 
    date = today + datetime.timedelta(day) 
    print "[%s, %s]" % (date, birthdays.get(date, 0))

來源

2011-05-09 13:37:09

。使用[range]（http://docs.djangoproject.com/en/dev/ref/models/querysets/#range）字段查找絕對是要走的路。 – zeekay 2011-05-09 13:48:13

但你不想避免'聚合'？最後一部分不起作用。 – zeekay 2011-05-09 13:56:05

爲什麼？爲什麼它不工作？ – 2011-05-09 14:04:15

（的人在接下來的X生日查詢集天）找到了很酷的解決方案！對我而言它有效！

from datetime import datetime, timedelta 
import operator 

from django.db.models import Q 

def birthdays_within(days): 

    now = datetime.now() 
    then = now + timedelta(days) 

    # Build the list of month/day tuples. 
    monthdays = [(now.month, now.day)] 
    while now <= then: 
     monthdays.append((now.month, now.day)) 
     now += timedelta(days=1) 

    # Tranform each into queryset keyword args. 
    monthdays = (dict(zip(("birthday__month", "birthday__day"), t)) 
       for t in monthdays) 


    # Compose the djano.db.models.Q objects together for a single query. 
    query = reduce(operator.or_, (Q(**d) for d in monthdays)) 

    # Run the query. 
    return Person.objects.filter(query)

但它得到一個在日期範圍內有生日的人的列表。你應該改變一下。

來源

2014-10-29 16:49:39 KravAn

Django的：總的生日每一天接下來的30天內

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