我要總結的列late_am_in
,late_am_out
,late_pm_in
,late_pm_out
並將結果total_hours 列時間。mysql如何總結列
SEC_TO_TIME(SUM(TIME_TO_SEC(STR_TO_DATE(late_pm_in, '%H:%I') - TIME_TO_SEC(STR_TO_DATE
(late_pm_out, '%H:%I')))) AS total_hours
我列的數據類型是VARCHAR。
謝謝!
我要總結的列late_am_in
,late_am_out
,late_pm_in
,late_pm_out
並將結果total_hours 列時間。mysql如何總結列
SEC_TO_TIME(SUM(TIME_TO_SEC(STR_TO_DATE(late_pm_in, '%H:%I') - TIME_TO_SEC(STR_TO_DATE
(late_pm_out, '%H:%I')))) AS total_hours
我列的數據類型是VARCHAR。
謝謝!
試試這個它的工作原理。
SEC_TO_TIME((TIME_TO_SEC(STR_TO_DATE(late_am_out, '%H:%i')) - TIME_TO_SEC(STR_TO_DATE(late_am_in, '%H:%i'))) + (TIME_TO_SEC(STR_TO_DATE(late_pm_out, '%H:%i')) - TIME_TO_SEC(STR_TO_DATE(late_pm_in, '%H:%i')))) AS total_hours
繼承人如何更新表計算總小時
Update Test SET total_hours = SEC_TO_TIME((TIME_TO_SEC(STR_TO_DATE(late_am_out, '%H:%i')) - TIME_TO_SEC(STR_TO_DATE(late_am_in, '%H:%i'))) + (TIME_TO_SEC(STR_TO_DATE(late_pm_out, '%H:%i')) - TIME_TO_SEC(STR_TO_DATE(late_pm_in, '%H:%i'))))
繼承人插入值
INSERT INTO Test
(`id`, `late_am_in`, `late_am_out`, `late_pm_in`, `late_pm_out`, `total_hours`)
VALUES
(7, '14:15', '16:15', '18:15', '19:19', SEC_TO_TIME((TIME_TO_SEC(STR_TO_DATE(late_am_out, '%H:%i')) - TIME_TO_SEC(STR_TO_DATE(late_am_in, '%H:%i'))) + (TIME_TO_SEC(STR_TO_DATE(late_pm_out, '%H:%i')) - TIME_TO_SEC(STR_TO_DATE(late_pm_in, '%H:%i')))))
;
可以共享所需的輸出時如何計算總小時這裏? – VeeK
減法不應該是另一種方式嗎?從中減去得到他們的時間量。 – Barmar
嗨,我只想通過添加列來獲得總小時數:late_am_in,late_am_out,late_pm_in,late_pm_out。有可能在MySQL? –