2016-04-23 77 views
0

我有一個名爲Profile的實體,它的主鍵實際上應該是指向RegisteredUser的外鍵。將約束外鍵添加到JPA中的實體

目前,這就是我想說的是,在Profile場既是它的主鍵和外鍵引用RegisteredUser

@Id 
@OneToOne 
@JoinColumn(foreignKey = @ForeignKey(name = "REGISTERED_USER_FK")) 
private RegisteredUser registeredUser; 

,並在RegisteredUser實體,我有以下幾點:

@OneToOne(cascade = CascadeType.ALL, mappedBy = "registeredUser") 
private Profile profile; 

不幸的是,當我運行SpringBootApplication,我有以下錯誤:

Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Column 'registered_user_username' cannot be null 
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) ~[na:1.8.0_40] 
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:62) ~[na:1.8.0_40] 
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45) ~[na:1.8.0_40] 
    at java.lang.reflect.Constructor.newInstance(Constructor.java:422) ~[na:1.8.0_40] 
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:404) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.Util.getInstance(Util.java:387) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:932) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3878) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3814) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2478) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2625) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2551) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1861) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.PreparedStatement.executeUpdateInternal(PreparedStatement.java:2073) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.PreparedStatement.executeUpdateInternal(PreparedStatement.java:2009) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.PreparedStatement.executeLargeUpdate(PreparedStatement.java:5094) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1994) ~[mysql-connector-java-5.1.38.jar:5.1.38] 
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:208) ~[hibernate-core-4.3.11.Final.jar:4.3.11.Final] 
    ... 42 common frames omitted 

當我嘗試運行此代碼:

User user = new User("blah"); 
repo.save(user); // using repositories to store entities to the db 

Profile profile = new Profile(user.getFirstName()); 

RegisteredUser rUser = new RegisteredUser(user.getUsername(), profile); 
rur.save(rUser); 

我檢查,看看用戶的用戶名是空的,但它不是......問題是,當我保存rUser ...

+1

列'registered_user_username'屬於哪個實體,'RegisteredUser'? – aribeiro

+0

爲什麼要從用戶分離配置文件?沒有用戶對象可以配置文件嗎? – WeMakeSoftware

+0

@aribeiro沒有這樣的專欄。我在'RegisteredUser'中有一個名爲'username'的字段,它也應該是'RegisteredUser'的主鍵,但也應該是一個引用'User'主鍵的外鍵...... – nbro

回答

1

根據JPA spec,您不能使用@Id註釋標註RegisteredUser

我無法想象爲什麼你需要從用戶單獨的配置文件,但如果你真的需要的話,你有幾種選擇:

選項A:

使用@Embeddable註釋上Profile。您不會爲Profile實體獲得單獨的表格,但您將在Java中獲得單獨的對象。

選項B:

Profile使用@ManyToOne。因此,用戶的生命週期將是這樣的:

  • 創建用戶
  • 創建簡歷
  • 保存配置文件
  • 設置用戶的配置文件來保存的配置文件
  • 保存用戶

你甚至可以在這些對象上具有相同的主鍵(查找建議here

選項C:

配置@OneToOne,但忘了具有具有相同的主鍵兩個實體的要求。