如何使sql查詢只返回1行？或者如何合併或2分的結果合併爲1

Question

問：

• 如何使合併或者2隊成績合併爲1？或
• 如何使它只返回1行？

表名：series_type

id| type| description 
1 | 0| No series (Any team win 1 will be the winner) 
2 | 1| Best of 3 (Any team wins 2 will be the winner else draw) 
3 | 2| Best of 5 (Any team wins 3 will be the winner else draw) 

表名：隊

 ID| name 
    1848158| LV 
     15| LGD 

表名：匹配

ID| series_id | series_type | league_id | start_time |radiant_name | dire_name | radiant_win 
1 |  8313 |   2 |  2096 | xxxxxxx1 |   LV |  LGD | true 
2 |  8313 |   2 |  2096 | xxxxxxx2 |   LGD |  LV | false 
3 |  8313 |   2 |  2096 | xxxxxxx3 |   LV |  LGD | false 
4 |  8313 |   2 |  2096 | xxxxxxx4 |   LV |  LGD | false 
5 |  8313 |   2 |  2096 | xxxxxxx5 |   LGD |  LV | false 

查詢：

SELECT series_id, team, SUM(Win) As Won, SUM(Loss) as Lost 
FROM 
(SELECT *,radiant_name as team, 
    CASE WHEN radiant_win = 1 THEN 1 ELSE 0 END as Win, 
    CASE WHEN radiant_win = 1 THEN 0 ELSE 1 END as Loss 
    FROM matches 
    UNION ALL 
    SELECT *,dire_name as team, 
    CASE WHEN radiant_win = 0 THEN 1 ELSE 0 END as Win, 
    CASE WHEN radiant_win = 0 THEN 0 ELSE 1 END as Loss 
    FROM matches 
) as temp 
WHERE series_id = 8313 
GROUP By team 
ORDER By Won, Lost DESC 

結果：當由series_id組

series_id| team| Won| Lost| 
    8313| LV| 5| 5| 

結果：當由茶組米

series_id| team| Won| Lost| 
    8313| LGD| 2| 3| 
    8313| LV| 3| 2| 

預期結果：我需要它按series_id

series_id| teamA| teamB| teamAWon| teamBWon| teamALost| teamBLost| 
    8313| LV| LGD|  3|  2|   2|   3| 

Answer 1

主要複雜因素是，每一個隊名可以在radiant_name或dire_name 0次或多次出現。因此，將團隊轉換爲每個團隊名稱中的一個列有點複雜。如果比賽有一個恆定的teamA和teamB列，然後是一列表明哪支球隊是光芒四射的，而另一列表明哪支球隊獲勝，那將更容易。

這是幾乎可以肯定不是最佳的，但它似乎工作：

-- create a two-column temp table with series ID and team name, insert rows from matches 
-- we'll wind up with one row per distinct radiant_name and distinct dire_name, 
-- so up to 4 rows for a series 
CREATE TEMPORARY TABLE IF NOT EXISTS tempteama AS 
select distinct series_id, radiant_name AS team 
from matches 
union 
select distinct series_id, dire_name AS team 
from matches; 

-- do this again in a second temp table, so we can join the two later 
-- (MySQL doesn't like to join temp tables against themselves) 
CREATE TEMPORARY TABLE IF NOT EXISTS tempteamb AS 
select distinct series_id, radiant_name AS team 
from matches 
union 
select distinct series_id, dire_name AS team 
from matches; 

-- join matches against the temp table to get final results 
select matches.series_id, 
teamA, 
teamB, 
sum(case when (radiant_name = teamA AND radiant_win=1) OR (dire_name=teamA AND radiant_win=0) then 1 else 0 end) AS teamA_win, 
sum(case when (radiant_name = teamB AND radiant_win=1) OR (dire_name=teamB AND radiant_win=0) then 1 else 0 end) AS teamB_win 
from matches 
join (
-- select just one row from the temp table. That gives us the combination of teams for the series. 
select tempteama.series_id, tempteama.team AS teamA, tempteamb.team AS teamB 
from tempteama 
join tempteamb on tempteama.series_id = tempteamb.series_id and tempteama.team != tempteamb.team 
limit 1 
) AS teamnames on teamnames.series_id = matches.series_id 
group by matches.series_id, teamA, teamB; 

你很可能做臨時表查詢作爲子查詢，在一些可讀性爲代價的。

Answer 2

我有兩個結果爲這個問題之一是用於爲Oracle SQL任何SQL和其它（如我用在它預言功能）

一個可以運行在任何SQL此解決方案： -

SELECT AB.SERIES_ID,TEAMA,TEAMB ,TEAMAWON,COUNT(STC.SERIES_ID)-TEAMAWON TEAMBWON, 
COUNT(STC.SERIES_ID)-TEAMAWON TEAMALOST, 
COUNT(STC.SERIES_ID)-(COUNT(STC.SERIES_ID)-TEAMAWON) TEAMBLOST FROM 
(
    SELECT MA.SERIES_ID,MA.RADIANT_NAME TEAMA,MA.DIRE_NAME TEAMB , 
    COUNT(RADIANT_WIN) TEAMAWON FROM MATCHES MA,SERIES_TYPE ST 
    WHERE MA.SERIES_TYPE=ST.TYPE 
    GROUP BY MA.SERIES_ID,MA.RADIANT_NAME,DIRE_NAME 
) AB, MATCHES STC 
WHERE (AB.SERIES_ID,AB.TEAMAWON) IN 
    (
    SELECT SERIES_ID,MAX(RADIANT_WIN) RAD 
    FROM 
    (
     SELECT MA.SERIES_ID,MA.RADIANT_NAME ,COUNT(RADIANT_WIN) RADIANT_WIN 
     FROM MATCHES MA,SERIES_TYPE ST 
     WHERE MA.SERIES_TYPE=ST.TYPE 
     GROUP BY MA.SERIES_ID,MA.RADIANT_NAME,DIRE_NAME 
    ) 
    GROUP BY SERIES_ID 
) AND STC.SERIES_ID=AB.SERIES_ID AND TEAMA IN (RADIANT_NAME,DIRE_NAME) 
GROUP BY AB.SERIES_ID,TEAMA,TEAMB ,TEAMAWON; 

現在我寫的解決方案誰正在尋求使用Oracle同樣的結果神諭人： -

SELECT SERIES_ID,GREATEST(RADIANT_NAME,DIRE_NAME) TEAMA, 
LEAST(RADIANT_NAME,DIRE_NAME) TEAMB ,max(RADIANT_WIN) TEAMAWON, 
SUM(RADIANT_WIN)-max(RADIANT_WIN) TEAMBWON, 
SUM(RADIANT_WIN)-max(RADIANT_WIN) TEAMALOST, 
SUM(RADIANT_WIN)-(SUM(RADIANT_WIN)-Max(RADIANT_WIN)) TEAMBLOST 
FROM 
(
    SELECT MA.SERIES_ID,MA.RADIANT_NAME,DIRE_NAME , 
    COUNT(RADIANT_WIN) RADIANT_WIN FROM MATCHES MA,SERIES_TYPE ST 
    WHERE MA.SERIES_TYPE=ST.TYPE 
    GROUP BY MA.SERIES_ID,MA.RADIANT_NAME,DIRE_NAME 
) GROUP BY SERIES_ID, 
    greatest(RADIANT_NAME,DIRE_NAME) ,least(RADIANT_NAME,DIRE_NAME);