PHP/MySQL的 - 將JSON數據到數據庫服務器BlueHost的，空的DB進入

Question

上這是一個使用腳本的JSON數據插入到上BlueHost的我的MySQL數據庫。我在循環內部和外部使用了各種echo語句，以確保JSON信息正確解析並且循環按預期工作。 Bluehost幫助文件告訴我使用SQL語句而不是SQLi或DBO。

<?php 
    $con = mysql_connect ("localhost:port", "username", "password"); 
    if (!$con) { 
     die('Could not reach database: Error Code ' . mysql_error() . "<br>"); 
    } else { 
     echo 'Connected to database. ' . "<br>"; 
    } 
    mysql_select_db ("db_name", $con); 

    $jsondata = file_get_contents('BFZ.json'); 
    $data = json_decode($jsondata, true); 

    $cards = $data['cards']; 

    // loop through the cards array and load each set of variables into the DB 
    for($i = 0; $i <= count($cards); $i++) { 
     $card_Name = $cards[$i]['name']; 
     $card_ManaCost = $cards[$i]['manaCost']; 
     $card_CMC = $cards[$i]['cmc']; 

     // Clear the variable from its last use 
     $card_Colors = ""; 

     // If the card has no color info, assign the text "Colorless" 
     if ($cards[$i]['colors'] == "") { 
      $card_Colors = "Colorless"; 
     // Else if the card has color info, convert the colors array into one long text variable 
     } else { 
      for($colorIndex = 0; $colorIndex < count($cards[$i]['colors']); $colorIndex++) { 
       $card_Colors = $card_Colors . $cards[$i]['colors'][$colorIndex] . " "; 
      } 
     } 

     // various bits to load into the DB 
     $card_Type = $cards[$i]['type']; 
     $card_Rarity = $cards[$i]['rarity']; 
     $card_Text = $cards[$i]['text']; 
     $card_Number = $cards[$i]['number']; 
     $card_Power = $cards[$i]['power']; 
     $card_Toughness = $cards[$i]['toughness']; 
     $card_MultID = $cards[$i]['multiverseid']; 
     $card_ID = $cards[$i]['id']; 

     // insert the data into the cards table 
     $sql = "INSERT INTO cards (card_ID, card_name, manaCost, cmc, colors, type, rarity, card_text, card_number, power, toughness, multiverseid) 
     VALUES ('$card_ID', '$card_Name', '$card_ManaCost', '$card_CMC', '$card_Colors', '$card_Type', '$card_Rarity', '$card_Text', '$card_Number', '$card_Power', '$card_Toughness', '$card_MultID')"; 
    } 
    if (!mysql_query($sql, $con)) { 
     die('Error: ' . mysql_error()); 
    } else { 
     echo "Data inserted correctly. <br>"; 
    } 
    $con->close(); 
?> 

最後的「數據正確插入」始終觸發，但我的數據庫只有存儲在CMC，電力，韌性好，multiverseid和無色的顏色條目0一個條目。 card_ID是我的主鍵，它是空白的。

要麼DB是沒有正確設置或我缺少的東西代碼。我會包含我的數據庫結構的屏幕截圖，但我不確定這是否允許。排序規則設置爲文本條目上的utf8_general_ci和Varchar以及數字上的int或smallint。 JSON結構如下：http://mtgjson.com/。

我不知道PHP和MySQL，直到兩年前天，以便原諒我，如果我失去了一些東西簡單。我讀過的所有其他問題似乎都沒有解決這個問題。

Answer 1

你mysql_query是外面的for循環，這就是爲什麼它僅被執行一次。它應該是

for($i = 0; $i <= count($cards); $i++) { 
    // 
    //... 
    // insert the data into the cards table 
    $sql = "INSERT INTO cards (card_ID, card_name, manaCost, cmc, colors, type, rarity, card_text, card_number, power, toughness, multiverseid)  VALUES ('$card_ID', '$card_Name', '$card_ManaCost', '$card_CMC', '$card_Colors', '$card_Type', '$card_Rarity', '$card_Text', '$card_Number', '$card_Power', '$card_Toughness', '$card_MultID')"; 

    //----> HERE instead 
    if (!mysql_query($sql, $con)) { 
     die('Error: ' . mysql_error()); 
    } else { 
     echo "Data inserted correctly. <br>"; 
    } 
} 

---

$card_Type = mysql_real_escape_string($cards[$i]['type']); 
$card_Rarity = mysql_real_escape_string($cards[$i]['rarity']); 

等