C++如何使用getline將完整的字符串存儲到字符串數組中？

Question

它得到第一個字符串和第一個雙倍後程序不會得到其他字符串。

for (int i = 0; i< NUM_MOVIES; i++) 
{ 
    cout << "Enter the name of the movie: "; 
    getline(cin, names[i]); 

    cout << "How much did " << names[i] << " earn <in millions>: "; 
    cin >> earnings[i]; 
    cout << endl; 
} 

Answer 1

你叫第二次getline你實際上是在閱讀一個換行符，因爲cin >>不丟棄換行符後的值它剛剛讀取。

所以你最終在這個閱讀不良數據的週期。試試這個：

getline(cin >> std::ws, names[i]); 

Answer 2

cin >> earnings[i]; 

這應該更正如下

getline(cin, earnings[i]) 

//示例程序

#include <iostream> 
#include <string> 
using namespace std; 

int main() 
{ 
    string names[10]; 
    string earnings[10]; 
    for (int i = 0; i< 10; i++) 
{ 
    cout << "Enter the name of the movie: "; 
    getline(cin, names[i]); 

    cout << "How much did " << names[i] << " earn <in millions>: "; 
    getline(cin, earnings[i]); 
    cout << endl; 
} 
cout<< names[0]<< names[1]<<"\n"; 
cout<<earnings[0] << earnings[1]<<"\n"; 
return 0; 

} 

Answer 3

的問題是，>>不讀過去的行結束所以下面的std::getline()這樣做，而不是抓住你的下一個輸入。

您可以使用std::ws（吸收空格字符）：

for (int i = 0; i< NUM_MOVIES; i++) 
{ 
    cin >> std::ws; // clear previous line 

    cout << "Enter the name of the movie: "; 
    getline(cin, names[i]); 

    cout << "How much did " << names[i] << " earn <in millions>: "; 
    cin >> earnings[i]; 
    cout << endl; 
}