Java：getSlope無法解析爲變量

Question

我在將getSlope（）打印到控制檯時出現問題，並且插入了（x1 - x2）/（y1 - y2）的任何值，Java最終除以零每次我運行程序。

坡類：

public class Slope { 
    private int x1; 
    private int x2; 
    private int y1; 
    private int y2; 

    public Slope(int a, int b, int c, int d) { 
     a = x1; 
     b = x2; 
     c = y1; 
     d = x2; 
    } 

    public void setSlope(int a, int b, int c, int d) { 
     x1 = a; 
     x2 = b; 
     y1 = c; 
     y2 = d; 
    } 

    public int getX() { 
     return (x1 - x2); 
    } 

    public int getY() { 
     return (y1 - y2); 
    } 

    public void sayThis() { 
     System.out.println(getX()/getY()); 
    } 
} 

testSlope類：

public class testSlope { 

    public static void main(String[] args) { 
     Slope slope = new Slope(10, 5, 1, 2); 
     slope.sayThis(); 
    } 
    //Exception in thread "main" java.lang.ArithmeticException:/by zero 
    // at Slope.getSlope(Slope.java:22) 
    // at Slope.sayThis(Slope.java:26) 
    // at testSlope.main(testSlope.java:5) 

} 

Answer 1

的問題是，你的構造函數是錯誤的。它應該是這樣的：

public Slope(int a, int b, int c, int d) { 
    x1 = a; 
    x2 = b; 
    y1 = c; 
    y2 = d; 
} 

Answer 2

公共類斜率{

private int x1; 
private int x2; 
private int y1; 
private int y2; 

public Slope(int a, int b, int c, int d) { 

    y2 = d; 
    y1 = c; 
    x2 = b; 
    x1 = a; 

    System.out.println(x1 - x2/y1 - y2); 
} 

public static void main(String[] args) { 
    Slope slope = new Slope(70, 80, 1, 2); 
} 

}