2016-11-28 63 views
0

,我發現了以下錯誤...的ActiveRecord :: AssociationTypeMismatch設備(#XXXX),得到的字符串(#XXXX)預期的ActiveRecord :: AssociationTypeMismatch設備(#XXXX),得到了預期的字符串(#XXXX)

我看不出來這個錯誤來自哪裏或如何解決它。任何人都可以解釋我的代碼出錯了嗎?

模型=

class Device < ActiveRecord::Base 

    has_many :from_links, class_name: "Link", foreign_key: "from_device" 
    has_many :to_links, class_name: "Link", foreign_key: "to_device" 

    def connected_devices 
    from_links.map(&:to_device) + to_links.map(&:from_device) 
    end 
end 

class Link < ActiveRecord::Base 

    belongs_to :from_device, class_name: "Device" 
    belongs_to :to_device, class_name: "Device" 
end 

LinksController =

class LinksController < ApplicationController 
    def create 
    @link = Link.new(link_params) 
    @device = Device.find_by(en: params[:link][:from_device]) 
    if @link.save 
     flash[:success] = "Link created." 
     redirect_to device_path(@device) 
    else 
     render 'new' 
    end 
    end 

private 

    def link_params 
    params.require(:link).permit(:from_device, :to_device, device_attributes: [:en]) 
    end 
end 

DevicesController =

class DevicesController < ApplicationController 

    def show 
    @device = Device.find(params[:id]) 
    @linked_devices = @device.connected_devices 
    end 

private 

    def device_params 
    params.require(:device).permit(:name, :en, :system_ip, :router_ip, :pop, :chassis_mode, :code_version) 
    end 

CreateLinks數據庫=

class CreateLinks < ActiveRecord::Migration[5.0] 
    def change 
    create_table :links do |t| 
     t.references :from_device 
     t.references :to_device 
    end 
    end 

創建新鏈接形式=

<% provide(:title, 'New Link') %> 
<h1> Create New Link </h1> 

<div class="row"> 
<div class="col-md-6 col-md-offset-3"> 
    <%= form_for(@link, url: links_path(params[:id])) do |f| %> 
    <%= render 'shared/error_messages', object: @link %> 

    <%= f.label :from %> 
    <%= f.select :from_device, options_for_select(@devices), :include_blank => true, class: 'form-control' %> 

    <%= f.label :to %> 
    <%= f.select :to_device, options_for_select(@devices), :include_blank => true, class: 'form-control' %> 

    <%= f.submit "Submit", class: "btn btn-primary" %> 
    <% end %> 
</div> 

+0

什麼是給出這個錯誤?我認爲它告訴你,無論varibable拋出的錯誤是一個字符串,它期望一個設備ID。 – gwalshington

+0

它說,這條線是錯誤的地方....提取源(繞線#8):def創建@link = Link.new(link_params)。點擊提交按鈕保存「創建新鏈接」即可。 –

+0

你也可以在問題中發佈你的參數嗎? – gwalshington

回答

0

在鏈接模式,你是這樣一個聯合體,以列from_deviceto_device。你想通過任何外鍵來關聯鏈接表。所以像這樣:

has_many :links, foreign_key: "from_device" 
has_many :links, foreign_key: "to_device" 

看看是否有幫助。您的設備型號也一樣。

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