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@JsonIgnore
@ManyToMany(mappedBy="awards", fetch=FetchType.LAZY)
private Set<Winner> winners = new HashSet<>();
得主實體
@ManyToMany(fetch=FetchType.LAZY)
@JoinTable(name="AWARD_ASSIGNMENT",
joinColumns={@JoinColumn(name="WINNER_ID", referencedColumnName="ID")},
inverseJoinColumns={@JoinColumn(name="AWARD_ID", referencedColumnName="ID")})
private Set<Award> awards = new HashSet<>();
我打電話這種休眠獲取方法
return getSession().createQuery("from Winner").list();
Hashcode方法等於在頒獎實體方法重載
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + (int) (id^(id >>> 32));
result = prime * result + ((winners == null) ? 0 : winners.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Award other = (Award) obj;
if (id != other.id)
return false;
if (winners == null) {
if (other.winners != null)
return false;
} else if (!winners.equals(other.winners))
return false;
return true;
}
得主實體
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((awards == null) ? 0 : awards.hashCode());
result = prime * result + (int) (id^(id >>> 32));
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Winner other = (Winner) obj;
if (awards == null) {
if (other.awards != null)
return false;
} else if (!awards.equals(other.awards))
return false;
if (id != other.id)
return false;
return true;
}
重寫equals和hashCode方法爲多對多關係,使用SET。
Do Award和Winner有equals/hashCode方法嗎?如果是的話請添加impl –
我已經添加了hashcode和equals方法,但是我仍然看到無限調用 – alowsarwar
我的意思是..將它們添加到您的帖子中讓我們看到 –