我無法提交表單; !!php curl否提交按鈕javascript
function loginSubmit()
{
if(!isSubmitted){
if(jQuery('#frmLoginStart').validationEngine('validate') != true)
return false;
isSubmitted = true;
document.frmLoginStart.submit();
}
}
<form action="/esube/logon/loginend.jsp" method="post" name="frmLoginStart" id="frmLoginStart">
<input type="hidden" value="tr_TR" name="rdLng" >
<input type="text" name="txtUsername" id="txtUsername">
<input type="password" name="txtPassword" id="txtPassword">
<a title="GİRİŞ" class="btnType2 button2" onclick="loginSubmit();return false;" name="btnSubmit" href="javascript:;"><span></span>GİRİŞ</a>
</form>
捲曲錯誤 捲曲提交點擊鏈接 沒有提交按鈕難度 我說土耳其語 請幫助
$ch = curl_init();
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/19.0.2");
curl_setopt($ch, CURLOPT_COOKIEFILE, getcwd().'/cookie.txt');
curl_setopt($ch, CURLOPT_URL, "https://esube1.ziraatbank.com.tr/esube/logon/loginstart.jsp");
$postu = "rdLng=tr_TR&txtUsername=51253433&txtPassword=976035";
curl_setopt($ch, CURLOPT_URL, 'https://esube1.ziraatbank.com.tr/esube/logon/loginend.jsp');
BUnasıl井現場anlamadım yazdığımkodlarıalmıyor
如果我正在閱讀這個權利,並且如果isSubmitted是您提交按鈕的ID,那麼您基本上是在詢問提交按鈕是否未被點擊並且未提交表單。我認爲這至少是一個起點。 – Jim 2013-03-12 15:59:07