將記錄放在沒有6個或更多不同地址的新表中

Question

如果重複的名稱超過6，並且同一名稱有6個不同的地址，則我不希望將它們輸出到KeepThese表：

harry baker 1 street 
harry baker 2 street 
harry baker 3 street 
harry baker 4 street 
harry baker 5 street 
harry baker 6 street 
donald ross 11th street 

所以哈利貝克應該從新表中排除。唐納德羅斯應該被列入新表。

這是現有查詢，我有：

SELECT F.* INTO KeepThese 
FROM final_output AS F 
INNER JOIN (SELECT DISTINCT F.fullName FROM final_output 
AS F LEFT JOIN (SELECT fullName FROM final_output 
AS F GROUP BY fullName HAVING COUNT(*) >=6) 
AS NamesToReject ON NamesToReject.fullName = F.fullName WHERE NamesToReject.ID IS NULL) 
AS NamesToKeep ON NamesToKeep.fullName = F.fullName; 

這將返回「輸入參數值NamesToReject.ID」 但是，這是最好的，我可以拿出。

Answer 1

如何：

SELECT * 
FROM final_output AS f 
LEFT JOIN (
    SELECT t.fullname 
    FROM final_output AS t 
    GROUP BY t.fullname 
    HAVING Count(t.fullname)>=6) AS Ex 
ON f.fullname=Ex.fullname 
WHERE Ex.fullname Is Null 

到目前爲止，少於6相同名稱的任何名稱和地址組合將被顯示。

如果添加了這個下一個語句，每個名稱中只有一個會顯示，並且隨機選擇該名稱的一個地址。

AND Nz([address],"None") In (
    SELECT TOP 1 Nz(address,"None") 
    FROM final_output t 
    WHERE t.fullname = f.fullname 
    ORDER BY fullname, Nz(address,"None"))