迭代jquery對象

Question

我試圖迭代並輸出選項屬性的值使用jquery each（）。我的代碼似乎輸出數組索引，而不是字符串值。爲什麼是這樣？這是我jsfiddle

var allQuestions = [ 
    { 
    question: "Who is Prime Minister of the United Kingdom?", 
    choices: ["David Cameron", "Gordon Brown", "Winston Churchill", "Tony Blair"], 
    correctAnswer:0 
    }]; 


$(info[0].choices).each(function(value){ 
    $('#answers').append($('<li>').text(value)); 
}); 

Answer 1

試試這個

$(info[0].choices).each(function(value){ 
    $('#answers').append($('<li>').text(this)); 

Answer 2

你是路過的，而不是價值指數：

var allQuestions = [{ 
    question: "Who is Prime Minister of the United Kingdom?", 
    choices: ["David Cameron", "Gordon Brown", "Winston Churchill", "Tony Blair"], 
    correctAnswer:0 
}]; 


$(info[0].choices).each(function(index, value){ 
    $('#answers').append($('<li>').text(value)); 
}); 

下面是一個例子小提琴：http://jsfiddle.net/436Lcvc4/

Answer 3

的$.each回調需要兩個參數index和value。添加value作爲第二個參數並改爲使用該參數。

Answer 4

你都弄得

$(selector).each() 

http://api.jquery.com/each/

與

$.each(array, callback) 

http://api.jquery.com/jquery.each/

你想使用第二種形式用於遍歷數組。