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我正在嘗試爲以代碼10開頭的員工創建報告....併爲他們應用特定的工作代碼。他們在表格中有一個糟糕的工作代碼。如何在 聲明中檢查條件?CASE聲明條件postgres
Example condition :
Apply job_code 'AC' for the employees that start with the code 10.
表1:customer_test
employee_code
Job_code_id
company_code
join_year
表2:C ompany_store
Job_code_id
JOB_CODE
Company_code
Join_year
SELECT
ct.employee_code,ct.job_code_id old,ct.company_code ,cs.job_Code_id new ,cs.job_code new code,
CASE
WHEN (ct.employee_code LIKE '10%') THEN CAST(cs.job_Code_id AS varchar) //I need to apply the condition here? apply the specific job code id based on the conditions.
ELSE CAST(cs.job_Code_id AS varchar)
END AS REPORT
FROM customer_test ct,company_store cs
WHERE ct.company_code=cs.company_code
and ct.job_code_id =cs.job_code_id
and ct.join_year=cs.join_year;
Thanks in advance.
我無法應用代碼'AC'。我將不得不爲代碼「AC」應用相應的ID。 – user2926497
你可以使用子查詢進行查找嗎?編輯於回答 – Andomar
謝謝。 Wil試着回來。 – user2926497