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我目前在學習Java,並且是Android的新手。下面是我的onCreate方法,在它的最後我有兩個EditText
字段,passT
(純文本)和keyT
(加密密鑰)。我想將這兩個參數作爲參數傳遞給我的加密方法(也在下面),並檢索結果並將其設置爲密碼EditText
。將參數從Activity.onCreate傳遞到其他方法
我想將該值設置爲用戶將輸入的電子郵件地址(emailT
,當前沒有設置爲EditText
的字段)。
public class ScreenNext extends Activity {
int key = 0;
static char ch;
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_screen_next)
EditText emailT;//Import EditTexts (Key and Email)
Button send = (Button) findViewById(R.id.bSend);//Import button1 (Send)
final EditText passT = (EditText) findViewById(R.id.etTogg);//passT variable for Password Text for EditText field
final EditText keyT = (EditText) findViewById(R.id.etKey);
final EditText passT = (EditText) findViewById(R.id.etTogg);//passT variable for Password Text for EditText field
send.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// TODO Auto-generated method stub
String keyText = keyT.getText().toString();
String passText = passT.getText().toString();
}
});
}//End onCreate
...
}
我的加密方法(包括他人的情況下,他們需要爲我的解決方案來觀察):
public static String message(String choice, String subKey, String message) {
int Option = Integer.parseInt(choice);//Must pareseInt
int key = Integer.parseInt(subKey);
message = message.toLowerCase();
//If the key is 26, prompt the user to change the key
if (key % 26 == 0) {
//Toast.makeText(getApplicationContext(), "You can't use a modulus of 26 as a key", Toast.LENGTH_LONG).show();
}
ScreenNext subcipher_1 = null;
String CipherTxt = subcipher_1.encrypt(message, key);
return CipherTxt;
}
// Message prompt method finished, now we create the method that has the
// encrypting algorithms
public static String encrypt(String Txt, int key) {
//local var cipherText of type string is init empty
String CipherTxt = "";//May be able to remove this'un
String cText="";
//enhanced for loop
// start at 0, go until "as long as input text"
for (int i = 0; i < Txt.length(); i++) {
//get a char from the string at index i (start at 0 work through to end of string)
// and store in local var extractedChar for type char
char extractedChar = Txt.charAt(i);
/* enhanced for loop
* start at 0, go until end of user entered cipherKeyValue
* either set to lowercase a or add one to the char
* uses the checkifz method
*/
for (int j = 0; j < key; j++) {
ScreenNext subcipher_1 = null;
if (subcipher_1.checkIfZ(extractedChar) == true) {
extractedChar = 'a';
} else {
extractedChar++;
}
CipherTxt= new StringBuilder().append(extractedChar).toString();
}
//add extracted char to builder object
//change object builder to string and assing to cipherText of type String
//create new object builder from StringBuilder class
cText = cText.concat(CipherTxt);
}
//Pass the cipherText value out of the method to whom ever called it
return cText;
}
Aaarrrrgggghhhhh聲明的變量。什麼是這種疾病造成的SO?我的眼睛在燃燒。我的大腦正在轉向泥漿並通過我的鼻孔泄漏出去。裏海的角魔正在用活鰻魚戳我。我的狗其實是一個狼人。任何在引用變量時鍵入「全局」一詞的人都應該被迫對基本編程進行測試。這些不是全球性的。根據定義,全局範圍的範圍和壽命等同於應用程序。這些是*類字段*或*類級變量*。它們不是全局的。他們是魔鬼的工作,應該在股份焚燒 – Simon 2013-04-10 20:02:31
好吧,所以任何人閱讀上述和質疑我的理智應該知道@丹尼斯好心編輯他的答案... – Simon 2013-04-10 20:04:16
感謝分配。但是,你看過我的加密方法嗎?我目前沒有任何keyText和passText變量的引用;我有其他人,因爲代碼最初是在Java IDE中編寫的。 我應該如何去實施這些新的變量來加密我的? – user2261396 2013-04-10 20:13:14