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我正在編寫過濾器搜索代碼,其中用戶從3個複選框列表中選擇至少一個選項,然後我必須爲選定的選項(複選框)編寫查詢。如果我嘗試運行我的代碼,那麼我將「查詢結果計數等於零」,這意味着$ count = 0「。以前,當我第一次編寫代碼時,它工作正常,但現在不能工作。爲什麼我的複雜'mysql'查詢總是返回查詢結果'count'爲0?
我的形式是:
我的MySQL表結構&數據是:lead_audit
結構:
ColumnName DataType Length
id int 11
supplier_id int 11
source varchar 255
client_id int 11
campaign_id varchar 255
data text
received datetime
errors blob
disposition varchar 255
id supplier_id source client_id campaign_id data received errors disposition
1 6 6 1 56 --- 2017-07-07 11:19:25 False Accepted
1 6 6 1 56 --- 2017-07-07 11:19:25 False Accepted
我的查詢是下面:
if(isset($request->suppliers) && $request->suppliers == 'suppliers'){
$results->leftjoin('suppliers AS s', 's.id', '=', 'l.supplier_id')
->addSelect('s.name AS Supplier')
->groupBy('s.name')
->orderBy('s.name');
}
if(isset($request->source) && $request->source == 'source'){
$results->addSelect('l.source AS Source')
->groupBy('l.source')
->orderBy('l.source');
//$results->leftjoin('source AS so', 'so.id', '=', 'l.source_id')
}
if(isset($request->campaign) && $request->campaign == 'campaign'){
$results->leftjoin('campaigns AS c', 'c.id', '=', 'l.campaign_id')
->addSelect('c.name AS Campaign')
->groupBy('c.name')
->orderBy('c.name');
}
if(isset($request->clients) && $request->clients == 'clients'){
$results->leftjoin('clients AS cl', 'cl.id', '=', 'l.client_id')
->addSelect('cl.name AS Client')
->groupBy('cl.name')
->orderBy('cl.name');
}
$queryResults = $results->addSelect('l.disposition AS Disposition')
->selectRaw('COUNT(*) as Count')
->whereBetween('l.received', [$start, $end])
->groupBy('l.disposition')
->orderBy('l.disposition')
->get()->toArray();
$count = count($queryResults);
echo "Count: ".$count;exit;
if($count > 0){
$results = array_map(function($item) {
return (array)$item;
}, $queryResults);
return Excel::create('my_excel_name', function($excel) use ($results) {
$excel->sheet('sheet_name', function($sheet) use ($results) {
$sheet->fromArray($results);
});
})->setFilename($filename)
->download('csv');
} else{
\Session::flash('error','No data has been found.');
return redirect('my_controller/create');
}
由此產生的查詢是:
array:1 [▼
0 => array:3 [▼
"query" => "select `s`.`name` as `Supplier`, `l`.`source` as `Source`, `c`.`name` as `Campaign`, `cl`.`name` as `Client`, `l`.`disposition` as `Disposition`, COUNT(*) as Count from `lead_audit` as `l` left join `suppliers` as `s` on `s`.`id` = `l`.`supplier_id` left join `campaigns` as `c` on `c`.`id` = `l`.`campaign_id` left join `clients` as `cl` on `cl`.`id` = `l`.`client_id` where `l`.`received` between ? and ? group by `s`.`name`, `l`.`source`, `c`.`name`, `cl`.`name`, `l`.`disposition` order by `s`.`name` asc, `l`.`source` asc, `c`.`name` asc, `cl`.`name` asc, `l`.`disposition` asc ◀"
"bindings" => array:2 [▼
0 => "2017-07-01"
1 => "2017-07-08"
]
"time" => 149.01
]
]
If I print below:
print_r($queryResults);
echo "Count: ".$count;exit;
then o/p
Array () Count: 0
爲什麼我得到$ count值總是'0'。我的代碼有什麼問題?
添加輸出的查詢:當你不知道你輸入的內容時,讀取一堆if語句並不真正。另外:減少到實際上只是該查詢。最後:在查詢後添加數據示例 –
查詢本身看起來很好。你可能會遇到一個問題,你需要定義比較的兩個日期,看看這篇文章:https://stackoverflow.com/questions/10398921/how-does-sql-server-decide-format-for-隱式日期時間轉換 – cars10m
感謝您的回覆。我也添加了表格結構。一般mysql在YYYY-MM-DD中存儲日期格式,我也在檢查相同的日期格式。這裏有趣的是它在本地服務器上正常工作,但在我們的服務器上無法正常工作。 –