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我無法理解會話如何通過mvc與php協同工作。 我的意大利麪條代碼像魅力一樣工作,並在mvc中實現它給我帶來麻煩。我可以成功登錄。問題是爲登錄用戶保留一個會話,並顯示例如註銷按鈕。通過MVC的PHP會話
我登錄的看法:
<div class="container">
<div class="login"><br>
<h4>Login</h4>
<?php
echo "<form method='POST' action='login-user.inc.php'>
<form class='login-inner'>
<input type='text' name='username' placeholder='Username' autocomplete='off' /><br /><br />
<input type='password' name='password' placeholder='Password' /><br /><br />
<input class='button' type='submit' name='submit' value='Login' />
</form>
</form>";
?>
</div>
</div>
登錄視圖經過登錄-user.inc.php:
<?php
namespace View;
use \Controller\SessionManager;
use \Util\Util;
use \Exceptions\CustomException;
require_once 'mvc/Util/Util.php';
Util::initRequest();
$messageToUser = "";
$controller = "";
if(isset($_POST['username']) && isset($_POST['password']) && !isset($_POST[Util::USER_SESSION_NAME])){
if(!empty($_POST['username']) && !empty($_POST['password'])){
$username = htmlentities($_POST['username'], ENT_QUOTES);
$password = htmlentities($_POST['password'], ENT_QUOTES);
try{
$controller = SessionManager::getController();
$controller->loginUser($username, $password);
echo "<p class = 'positiveMessageBox'>You are logged in! :) Welcome!</p>";
}catch(CustomException $ex){
echo "<p class = 'warningMessageBox'>".$ex->getMessage()."</p>";
}catch(\mysqli_sql_exception $ex){
echo "<p class = 'negativeMessageBox'>An error in connection with database occurred! Please contact administration of this website.</p>";
}finally{
SessionManager::storeController($controller);
}
}else{
echo "<p class = 'warningMessageBox'>Both username field and password field have to be filled! Try again!</p>";
}
}
@$_GET['page'] = $_SESSION['pageId'];
include Util::VIEWS_PATH."redirect.php";
?>
我sessionhandler.php:
<?php
namespace Controller;
use Controller\Controller;
/**
* This class stores and retrieves session data
* @package Controller
*/
class SessionManager{
const CONTROLLER_KEY = 'controller';
const BROWSER_COMMENT_COUNT_KEY = 'browserCommentsCount';
private function __construct(){}
/**
* This method stores controller instance in the current session
* @param \Controller\Controller $controller
*/
public static function storeController(Controller $controller){
$_SESSION[self::CONTROLLER_KEY] = serialize($controller);
}
/**
* This method returns Controller instance
* If Controller instance do not exists then returns new instance
* @return \Controller\Controller
*/
public static function getController(){
if(isset($_SESSION[self::CONTROLLER_KEY]))
return unserialize($_SESSION[self::CONTROLLER_KEY]);
else
return new Controller();
}
}
?>
我util,這是首先用session_start()初始化的:
<?php
namespace Util;
/**
* Utility class
* @package Util
*/
final class Util{
const VIEWS_PATH = 'src/view/';
const CSS_PATH = 'src/css/';
const IMG_PATH = 'src/img/';
const USER_SESSION_NAME = 'username';
private function __construct(){}
/**
* This method initialises autoload function and starts session
* This method should should be called first in any PHP page that receiving a HTTP request
*/
public static function initRequest(){
\session_start();
self::initAutoload();
}
private static function initAutoload(){
spl_autoload_register(function($class) {
require_once 'mvc/' . \str_replace('\\', '/', $class) . '.php';
});
}
}
?>
這通過控制器等。這是成功登錄後會發生什麼。
public function login(LoginData $userLoginData){
$userDAO = new UserDAO();
if($userDAO->doUsernameExistInDB($userLoginData->getUsername())){
if(password_verify($userLoginData->getPassword(), $userDAO->getUserPasswordFromDB($userLoginData->getUsername()))){
session_regenerate_id();
$_SESSION['username'];
}else
throw new CustomException("Password do not match with username you entered!");
}else{
throw new CustomException("We could not find the username you entered.");
}
}
最後是應該顯示註銷按鈕redirect.php:
我不知道爲什麼在登錄時會話未初始化它不斷告訴我,我當我已經擁有時,仍然可以登錄。我在這裏錯過了什麼?
謝謝你的回答!我認爲這實際上是問題。我能夠將登錄函數更改爲$ _SESSION ['username'] = $ _POST ['username'],這對應於輸入的用戶名。不過,我想知道如何能夠改變Util類中的常量。我希望能夠通過$ _POST訪問USER_SESSION_NAME,但無法訪問。有任何想法嗎? – Einstein
好吧完美!請毫不猶豫地將您的問題設置爲已解決,謝謝! –
在解決它以適合每個登錄用戶之前,我通過將常量「USER_SESSION_NAME」設置爲我當前使用的用戶登錄時進行調試,但仍然是同樣的問題。我將會話名稱更改爲我目前正在使用的用戶,現在它可以正常工作。我想我必須使用發佈的用戶名來實現會話名稱。謝謝您的幫助。 – Einstein