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我有以下工作SQL查詢,並將其工作正常如何寫SQL在laravel連接查詢
我已經在數據庫測試(SQL編輯器)
select b.name "group_id", b.name "group_name",bt.name "group_type",a.location_name ,b.total_users ,group_concat(u.full_name) "members",group_concat(ui.picture_1) "pictures",(select picture_1 from user_pictures where id IN
(select uii.profile_id from users as uii where uii.id = b.owner_id)) as owner_images
from users u
inner join groups b
inner join group_types bt
inner join group_users bu
inner join addresses a
inner join user_pictures ui
on
u.id=bu.user_id and
b.id=bu.group_id and
bt.id=b.type_id and
a.id=b.address_id and
ui.id =u.profile_id and
bu.status="active" and bu.user_id=3 and b.owner_id <> 3
group by b.name, bt.name, bu.status
樣本OUTPUT
問題:我想將它轉換成laravel格式。
我想除了圖片領域
$groupInfo = DB::table('users as u')
->join('group_users as bu', 'bu.user_id', '=', 'u.id')
->join('groups as b', 'b.id', '=', 'bu.group_id')
->join('group_types as bt', 'bt.id', '=', 'b.type_id')
->join('addresses as a', 'a.id', '=', 'b.address_id')
->join('user_images as ui', 'ui.id', '=', 'u.profile_id')
->where('bu.status', '=', 'active')
->where('bu.user_id', '=', $user_id)
->where('b.owner_id', '<>', $user_id)
->groupBy('b.name')
->groupBy('bt.name')
->groupBy('bu.status')
->select('b.id as group_id','b.name as group_name','bt.name as group_type','b.owner_id','a.location_name','b.total_users',DB::raw('group_concat(u.id) as members'),DB::raw('group_concat(ui.image_1) as images'))
->get();
return $groupInfo;
如何添加按照以上laravel查詢SQL內部查詢下面讓一切?
(select picture_1 from user_pictures where id IN
(select uii.profile_id from users as uii where uii.id = b.owner_id)) as owner_pictures
我怎樣才能得到我的查詢執行?