調用未定義的方法mysqli_stmt :: fetchColumn（）

Question

我試圖讓行數從SQL查詢

require_once("inc/db_const.php"); 
$date=$_GET['date_rdv']; 
$mysqli= new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME); 
if($mysqli->connect_errno) 
{ 
    echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>"; 
    exit(); 
} 
$query_check="SELECT count(*) FROM planning_cl WHERE date_plannig = ?"; 
$statement_check = $mysqli->prepare($query_check); 
$statement_check->bind_param('s',$date); 
$statement_check->execute(); 
$rdv_verif=$statement_check->fetchColumn(); 
echo $rdv_verif; 

返回，但它表明我這個錯誤

r: Call to undefined method mysqli_stmt::fetchColumn() 

可以在任何人給我任何解決方案來解決這個問題

Answer 1

沒有mysqli_stmt::fetchColumn()在庫MySQLi看Documentation這是一個PDO 方法。

對於MySQLi的使用mysqli_stmt_num_rows ()

$rdv_verif=$statement_check->mysqli_stmt_num_rows(); 
echo $rdv_verif; 

Answer 2

您需要使用$statement_check->fetch();

require_once("inc/db_const.php"); 
$date=$_GET['date_rdv']; 
$mysqli= new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME); 
if($mysqli->connect_errno) 
{ 
    echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>"; 
    exit(); 
} 
$query_check="SELECT count(*) as cnt FROM planning_cl WHERE date_plannig = ?"; 
$statement_check = $mysqli->prepare($query_check); 
$statement_check->bind_param('s',$date); 
$statement_check->execute(); 
$line=$statement_check->fetch(PDO::FETCH_ASSOC); 
$rdv_verif = $line['cnt'] 
echo $rdv_verif; 

Answer 3

作爲一個類似的問題看出：

Why is PDO fetchColumn() not working here

---

如果你想獲得的行數返回使用rowCount

// ... 
$rows = $stmt->rowCount(); 

echo 'Rows found '.$rows; 
// ... 

---

哪一世ŝ得到你需要的行數的最適當的方式，所以你的情況：

$rdv_verif=$statement_check->rowCount();