openerp 7 ir.sequence增加2個錯誤。

Question

在我的情況下，當我打開表單時顯示+1序列號。但是，當我保存記錄，它由1再次遞增這意味着我的序列號現在這個樣子：

• EMP0010
• EMP0012
• EMP0014

是它的OpenERP的問題或者我在代碼中丟失了什麼？

'register_no': fields.char('Register No', size=32, help='Register No', readonly=True), # employer wise ,estate wise 
     'employer_no': fields.char('Employer No', type='char', readonly=True), 

_defaults = { 
'register_no': lambda obj, cr, uid, context: '/', 
'employer_no': lambda obj, cr, uid, context: '/', 
} 

你可以在我的代碼here

我評論

def create(self, cr, uid, values, context=None): 
     values['register_no'] = self.pool.get('ir.sequence').get(cr, uid, 'bpl.worker') 
     values['employer_no'] = self.pool.get('ir.sequence').get(cr, uid, 'bpl.employer') 
     return super(bpl_worker_registration, self).create(cr, uid, values, context=context) 

Answer 1

你叫ir.sequence方法兩次，一個從創建一看

高清創建（self，cr，uid，values，context = None）：

個

values['register_no'] = self.pool.get('ir.sequence').get(cr, uid, 'bpl.worker') 
values['employer_no'] = self.pool.get('ir.sequence').get(cr, uid, 'bpl.employer') 
return super(bpl_worker_registration, self).create(cr, uid, values, context=context) 

和第二從默認

_defaults = {

'register_no': lambda obj, cr, uid, context: obj.pool.get('ir.sequence').get(cr, uid, 'bpl.worker'), 
'employer_no': lambda obj, cr, uid, context: obj.pool.get('ir.sequence').get(cr, uid, 'bpl.employer'), 

} 

它沒有任何意義，調用兩個時間。只從_default或從創建方法撥打電話