2016-03-03 139 views
2

我已經通過電子郵件地址(電子郵件區分大小寫)得到 的驗證,我仍然收到554郵件被拒絕:電子郵件地址未驗證拒絕來自SES。但是,當我嘗試使用同一封電子郵件從Amazon SES控制檯發送電子郵件時,它工作正常。如果我的電子郵件沒有通過驗證,那麼從控制檯也不應該工作。無法理解正在發生的事情。554郵件被拒絕的電子郵件地址未驗證。亞馬遜ses-java

public class AmazonSESSample { 

    static final String FROM = "from email"; 
    static final String TO = "to email"; 

    static final String BODY = "This email was sent through the Amazon SES SMTP interface by using Java."; 
    static final String SUBJECT = "Amazon SES test (SMTP interface accessed using Java)"; 

    // Supply your SMTP credentials below. Note that your SMTP credentials are different from your AWS credentials. 
    static final String SMTP_USERNAME = "SMTP USER NAME"; 
    static final String SMTP_PASSWORD = "SMTP PWD"; 

    static final String HOST = "email-smtp.us-east-1.amazonaws.com";  

    // Port we will connect to on the Amazon SES SMTP endpoint. We are choosing port 25 because we will use 
    // STARTTLS to encrypt the connection. 
    static final int PORT = 25; 

    public static void main(String[] args) throws Exception { 

     // Create a Properties object to contain connection configuration information. 
     Properties props = System.getProperties(); 
     props.put("mail.transport.protocol", "smtp"); 
     props.put("mail.smtp.port", PORT); 

     // Set properties indicating that we want to use STARTTLS to encrypt the connection. 
     // The SMTP session will begin on an unencrypted connection, and then the client 
     // will issue a STARTTLS command to upgrade to an encrypted connection. 
     props.put("mail.smtp.auth", "true"); 
     props.put("mail.smtp.starttls.enable", "true"); 
     props.put("mail.smtp.starttls.required", "true"); 

     // Create a Session object to represent a mail session with the specified properties. 
     Session session = Session.getDefaultInstance(props); 

     // Create a message with the specified information. 
     MimeMessage msg = new MimeMessage(session); 
     msg.setFrom(new InternetAddress(FROM)); 
     msg.setRecipient(Message.RecipientType.TO, new InternetAddress(TO)); 
     msg.setSubject(SUBJECT); 
     msg.setContent(BODY,"text/plain"); 

     // Create a transport.   
     Transport transport = session.getTransport(); 

     // Send the message. 
     try 
     { 
      System.out.println("Attempting to send an email through the Amazon SES SMTP interface..."); 

      // Connect to Amazon SES using the SMTP username and password you specified above. 
      transport.connect(HOST, SMTP_USERNAME, SMTP_PASSWORD); 

      // Send the email. 
      transport.sendMessage(msg, msg.getAllRecipients()); 
      System.out.println("Email sent!"); 
     } 
     catch (Exception ex) { 
      System.out.println("The email was not sent."); 
      System.out.println("Error message: " + ex.getMessage()); 
      ex.printStackTrace(); 
     } 
     finally 
     { 
      // Close and terminate the connection. 
      transport.close();   
     } 
    } 
} 
+0

我們正面臨同樣的問題。您有什麼解決方案嗎? – MasterCode

回答

0

我有同樣的問題,它原來是一個簡單的盲複製粘貼問題。目前,SES有3個地區。根據您設置ID的區域,必須相應地修改HOST變量。

static final String HOST = "email-smtp.us-east-1.amazonaws.com"; 

這解決了我的問題。之後,如果您想將電子郵件發送至未經驗證的電子郵件地址,則必須將您的設置移出沙箱。

http://docs.aws.amazon.com/ses/latest/DeveloperGuide/request-production-access.html