2017-02-16 155 views
1

我想要SSH服務器使用python paramiko包。通過給私鑰作爲字符串ssh到服務器 - paramiko aws lambda問題

當我試圖使用「pem」密鑰ssh到服務器然後它工作,但當我嘗試通過採取字符串中的私鑰內容它顯示錯誤。

下面是代碼和輸出:

import paramiko<br/> 
import StringIO<br/> 
content="-----BEGIN RSA PRIVATE KEY----- MIIEowIBAAKCAQE ----whatever content"<br/> 
private_key = StringIO.StringIO(content)<br/> 
k = paramiko.RSAKey.from_private_key(private_key)<br/> 
c = paramiko.SSHClient()<br/> 
c.set_missing_host_key_policy(paramiko.AutoAddPolicy())<br/> 
host="XX.XX.XX.XXX"<br/> 
c.connect(hostname = host,username="ec2-user", pkey = k)<br/> 
print "Connected to " + host`<br/> 

輸出:

Traceback (most recent call last):<br/> 
    File "one.py", line 6, in <module><br/> 
    k = paramiko.RSAKey.from_private_key(private_key)<br/> 
    File "/home/ec2-user/abc/local/lib/python2.7/site-packages/paramiko/pkey.py", line 217, in from_private_key<br/> 
    key = cls(file_obj=file_obj, password=password)<br/> 
    File "/home/ec2-user/abc/local/lib/python2.7/site-packages/paramiko/rsakey.py", line 42, in __init__<br/> 
    self._from_private_key(file_obj, password)<br/> 
    File "/home/ec2-user/abc/local/lib/python2.7/site-packages/paramiko/rsakey.py", line 167, in _from_private_key<br/> 
    data = self._read_private_key('RSA', file_obj, password)<br/> 
    File "/home/ec2-user/abc/local/lib/python2.7/site-packages/paramiko/pkey.py", line 277, in _read_private_key<br/> 
    raise SSHException('not a valid ' + tag + ' private key file')<br/> 
paramiko.ssh_exception.SSHException: not a valid RSA private key file<br/> 

任何人都可以提出可能是什麼問題呢?

回答

1

私鑰文件是一個多行文件。

因此,將它作爲字符串使用時,請保留內容結構以保持其有效性。

content = """-----BEGIN RSA PRIVATE KEY----- 
       MIIEpgSIJOBAAKCAQEAqwH5fWIbtFRankLqvtnQ6OKwmIa49i 
       .......................................... 
       -----END RSA PRIVATE KEY-----""" 

private_key = StringIO.StringIO(content) 
k = paramiko.RSAKey.from_private_key(private_key) 
+1

franklinsijo謝謝。它對我來說非常合適。 –