給定的輸入字符串,如「1,2,3..6..8,9..11」,我們必須把它轉換成「1,2,3,4,5,6,7,8,9,10,11」。所以基本上我們必須填充由點提到的範圍。以下是我的解決方案。有沒有更好的方法來解決這個問題?我們可以進一步優化嗎?
public class FlattenAString {
public static String flattenAString(String input) {
StringBuilder sbr = new StringBuilder("");
StringBuilder current = new StringBuilder("");
StringBuilder next = new StringBuilder("");
int i = 0;
while (i < input.length()) {
if (input.charAt(i) == '.') {
i = i + 2;
while (i != input.length() && input.charAt(i) != '.' && input.charAt(i) != ',') {
next.append(input.charAt(i));
i++;
}
int currentInt = Integer.parseInt(current.toString());
int nextInt = Integer.parseInt(next.toString());
appendFromCurrentTillPrevToNextInt(currentInt, nextInt, sbr);
current = next;
next = new StringBuilder("");
} else if (input.charAt(i) == ',') {
sbr.append(current);
sbr.append(',');
current = new StringBuilder("");
i++;
} else {
current.append(input.charAt(i));
i++;
}
}
sbr.append(current);
return sbr.toString();
}
private static void appendFromCurrentTillPrevToNextInt(int current, int val, StringBuilder sbr) {
for (int i = current; i < val; i++) {
sbr.append(i);
sbr.append(',');
}
}
}
對Code Review(https://codereview.stackexchange.com)來說這似乎是一個很好的問題。 –
如果給出'[1..n]'的所有數字都存在,那麼我們不能只取第一個和最後一個數字,並填充它們之間的所有其他數字? – Oswald
@Oswald:這確實是最好的解決方案,因爲沒有缺失整數。謝謝 –