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任何人都可以幫我解決這個SQL錯誤嗎?
如何使用xampp將它連接到phpmyadmin中的數據庫? 如果您認爲它有問題,請隨時糾正我的代碼。連接phpmyadmin
Imports System.Data.SqlClient
Imports MySql.Data.MySqlClient
Public Class Form1
Dim con As SqlConnection
Dim com As SqlCommand
Private Sub Form1_Load(sender As System.Object, e As System.EventArgs) Handles MyBase.Load
con = New SqlConnection
con = New SqlCommand
con.ConnectionString = "initial catalog=student;user id=sa;pwd="
con.Open()
con.Connection = con
End Sub
Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click
If TextBox1.Text = " " Or TextBox2.Text = " " Or TextBox3.Text = " " Then
MsgBox("Please fill all the details")
Exit Sub
End If
com.CommandText = "insert into stud values('" & TextBox1.Text & "','" & TextBox2.Text & "','" & TextBox3.Text & "')"
com.ExecuteNonQuery()
MsgBox("1 record is stored successfully")
TextBox1.Clear()
TextBox2.Clear()
TextBox3.Clear()
End Sub
End Class
您是否閱讀過錯誤消息並查看了它所提到的幾行? 'con'只能是Command **或** Connection對象。還有更多的錯誤。您應該對IDisposable,COnnection Pooling和SQL參數進行一些研究。 – Plutonix
另外MySQL和SQL Server是兩個非常不同的東西 - 沒有一個'System.Data.SqlClient'對象可以與MySQL一起工作。你也想訪問www.connectionstrings.com – Plutonix