無法從servlet訪問JSP下拉值

Question

我有一個jsp，有兩個下拉位置和部門。

根據通過Ajax的位置值填充部門下拉列表的值。

但是當我嘗試保存頁面時，如果選擇了部門中的第一項下拉菜單，我無法訪問部門下拉列表的值。

但是如果選擇第二或第三項，則可以從servlet訪問它。

<form id="form1" name="crtdocfrm" action="CreateLocation" method="post"> 
    <fieldset width="50%"> 
    <legend>Division</legend> 
    <table id="table1"> 
     <tr class="tr_stylebutton"> 
     <td>Location Name</td> 
     <td><select name="locName" onChange="showDept(this.value)"> 
      <option value="-1">--select--</option> 
      <% 
      Iterator itrLocation = arlLocation.iterator(); 
      while (itrLocation.hasNext()) { 
      %> 
      <option value=<%=itrLocation.next()%>><%=itrLocation.next()%> 
      </option> 
      <%}%> 
     </select></td> 
     </tr> 

     <tr class="tr_stylebutton"> 
     <td>Department Name</td> 
     <td> 
      <select name="ddDeptName" onChange="alert(this.value)"></select> 
     </td> 

     </tr> 
     <tr class="tr_stylebutton"> 
     <td>Division ID</td> 
     <% 
      LocationPolulate lp = new LocationPolulate(); 
      int Div_Id = lp.DivisionId(); 
     %> 
     <td><input type="text" name="divID" disabled="true" value=<%=Div_Id + 1%>/></td> 
     </tr> 

     <tr class="tr_stylebutton"> 
     <td>Division Name</td> 
     <td><input type="text" name="divName" value=""/></td> 
     </tr> 
    </table> 

    <table border="0" width="55%" align="left" id="table-button"> 
     <tr class="tr_stylebutton"> 
     <td align="right"><input type="submit" value="Save" class="button"/></td> 
     <td align="left"><input type="submit" value="Cancel" class="button"/></td> 
     </tr> 
    </table> 
    </fieldset> 
    &nbsp;&nbsp;<br/> 
</form> 

的Servlet

protected void doPost(HttpServletRequest request, HttpServletResponse response) 
     throws ServletException, IOException { 
    processRequest(request, response); 

    int intLocId = Integer.parseInt(request.getParameter("locName")); 
    String strDivNm = (String) request.getParameter("divName"); 
    int intDeptId = Integer.parseInt(request.getParameter("ddDeptName")); 

    LocationPolulate lp = new LocationPolulate(); 
    int Res = lp.InsertDivision(strDivNm, intLocId, intDeptId); 

    if (Res == 0) { 
     request.setAttribute("Errmsg", "Error Cannot Save Division"); 
     RequestDispatcher dis1 = getServletContext().getRequestDispatcher("/AddDivision"); 
     dis1.forward(request, response); 
    } else { 
     int Div = lp.DivisionId(); 
     request.setAttribute("succmsg", "Successfully saved Division with division id:" + Div); 
     RequestDispatcher dis1 = getServletContext().getRequestDispatcher("AddDivision.jsp"); 
     dis1.forward(request, response); 
    } 
} 

任何想法？

Answer 1

對不起，添加代碼作爲評論的一部分...我無法適應整個代碼，所以我不得不添加評論..有錯誤的Java腳本。下面給出了正確的一個。謝謝所有您的建議...

function stateChanged() 
{ 
    if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete") 
    { 
     var showdata = xmlHttp.responseText; 
     var strar = showdata.split(":"); 

     if(strar.length==1) 
     { 
      document.getElementById("locName").focus(); 
      alert("Please Select location Id"); 
     } 
     else if(strar.length>1) 
     { 
      option=new Option("---Select---", -1); 

      document.crtdocfrm.ddDeptName.options[0]=option; 
      for(var i=1;i<strar.length-1;i=i+2) 
      { 
       option=new Option(strar[i+1], strar[i]); 
       document.crtdocfrm.ddDeptName.options[(i-1)/2+1]=option; 
      } 
     } 
    } 
} 

我收到來自另一個JSP相同的字符串的標識和名稱，劈裂它來獲得不同的部門ID和名稱的值。