在推文中找到匹配的URL

Question

我參與了一個需要刪除URL的項目

在Ruby 1.8.7中是否有一個很好的正則表達式來匹配任何URL？

PS - 我有一個

/(?i)\b((?:[a-z][\w-]+:(?:\/{1,3}|[a-z0-9%])|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}\/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»「」‘’])\/*)/x 

的正則表達式是在http://www.rubular.com/r/UFDveGLNGt用幾個例子弦 我如何匹配像fb.me或goo.gl或google.com網站？

Answer 1

關於什麼：

require 'uri' 
URI.regexp 

這個計算結果爲：

/ 
    ([a-zA-Z][\-+.a-zA-Z\d]*):       (?# 1: scheme) 
    (?: 
     ((?:[\-_.!~*'()a-zA-Z\d;?:@&=+$,]|%[a-fA-F\d]{2})(?:[\-_.!~*'()a-zA-Z\d;\/?:@&=+$,\[\]]|%[a-fA-F\d]{2})*)     (?# 2: opaque) 
    | 
     (?:(?: 
     \/\/(?: 
      (?:(?:((?:[\-_.!~*'()a-zA-Z\d;:&=+$,]|%[a-fA-F\d]{2})*)@)?  (?# 3: userinfo) 
       (?:((?:(?:[a-zA-Z0-9\-.]|%\h\h)+|\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}|\[(?:(?:[a-fA-F\d]{1,4}:)*(?:[a-fA-F\d]{1,4}|\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})|(?:(?:[a-fA-F\d]{1,4}:)*[a-fA-F\d]{1,4})?::(?:(?:[a-fA-F\d]{1,4}:)*(?:[a-fA-F\d]{1,4}|\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}))?)\]))(?::(\d*))?))? (?# 4: host, 5: port) 
      | 
      ((?:[\-_.!~*'()a-zA-Z\d$,;:@&=+]|%[a-fA-F\d]{2})+)     (?# 6: registry) 
      ) 
     | 
     (?!\/\/))       (?# XXX: '\/\/' is the mark for hostport) 
     (\/(?:[\-_.!~*'()a-zA-Z\d:@&=+$,]|%[a-fA-F\d]{2})*(?:;(?:[\-_.!~*'()a-zA-Z\d:@&=+$,]|%[a-fA-F\d]{2})*)*(?:\/(?:[\-_.!~*'()a-zA-Z\d:@&=+$,]|%[a-fA-F\d]{2})*(?:;(?:[\-_.!~*'()a-zA-Z\d:@&=+$,]|%[a-fA-F\d]{2})*)*)*)?     (?# 7: path) 
     )(?:\?((?:[\-_.!~*'()a-zA-Z\d;\/?:@&=+$,\[\]]|%[a-fA-F\d]{2})*))?     (?# 8: query) 
    ) 
    (?:\#((?:[\-_.!~*'()a-zA-Z\d;\/?:@&=+$,\[\]]|%[a-fA-F\d]{2})*))?     (?# 9: fragment) 
    /x 

這將可能是比什麼都好，我們可以來這裏（否則考慮將它提交給ruby）。