Python pandas to_json（）無效格式

Question

我在使用JSON字符串輸出時遇到了問題。我使用的製表符分隔的CSV文件，它看起來像這樣：

date  time  loc_id country name sub1_id sub2_id type 
2014-09-11 00:00:01 179  US  acmnj 269  382  ico 
2014-09-11 00:00:01 179  US  acmnj 269  382  ico 
2014-09-11 00:00:01 179  GB  acmnj 269  382  ico 
2014-09-11 00:00:01 179  US  acmnj 269  382  ico 
2014-09-11 00:00:02 179  GB  acmnj 269  383  ico 
2014-09-11 00:00:02 179  JP  acmnj 269  383  ico 

代碼如下所示：

df = pd.read_csv('log.csv',sep='\t',encoding='utf-16') 
count = df.groupby(['country','name','sub1_id','sub2_id','type']).size() 
print(count.order(na_position='last',ascending=False).to_frame().to_json(orient='index')) 

輸出看起來像這樣（前幾行）：

{"["US","acmnj",269,383,"ico"]":{"0":76174},"["US","acmnj",269,382,"ico"]":{"0":73609},"["IT","acmnj",269,383,"ico"]":{"0":54211},"["IT","acmnj",269,382,"ico"]":{"0":52398},"["GB","acmnj",269,383,"ico"]":{"0":41346},"["GB","acmnj",269,382,"ico"]":{"0":40140},"["US","acmnj",269,405,"ico"]":{"0":39482},"["US","acmnj",269,400,"ico"]":{"0":39303},"["US","popcdd",178,365,"ico"]":{"0":33168},"["IT","acmnj",269,400,"ico"]":{"0":33026},"["IT","acmnj",269,405,"ico"]":{"0":32824},"["IT","achrfb141",141,42,"ico"]":{"0":26986},"["GB","acmnj",269,405,"ico"]":{"0":25895},"["IN","acmnj",269,383,"ico"]":{"0":25647},"["GB","acmnj",269,400,"ico"]":{"0":25488...

我想在PHP中加載這個輸出，但當我試圖解碼這個時，我得到NULL。我使用JSON驗證器來檢查字符串，它是無效的。我也試過沒有orient參數，但我得到無效的JSON格式。

Answer 1

這似乎是大熊貓的問題。我再現了你的錯誤。 「拆分」，「記錄」，「索引」，「列」和「值」可能會帶來幾個不同的結果東方參數：

DataFrame.to_json

就你而言，它好像是'分裂'，'記錄'和'值'的工作，但'索引'和'列'不是。

您可以使用Python中json模塊快速測試：

df = pd.read_csv('log.csv',sep='\t',encoding='utf-16') 
count = df.groupby(['country','name','sub1_id','sub2_id','type']).size() 
f=count.order(ascending=False).to_frame() 
json.loads(f.to_json(orient='index')) # This failed for me 
json.loads(f.to_json(orient='records')) #This worked