我想從JSON webservice中將標題,整數和url保存到SQLite數據庫中。我使用的代碼來做到這一點,當我使用另一個url時,它是完美的工作,但現在我總是得到這個例外,我想保存每個JSON對象:從JSON將數據保存到SQLite Android
E/SQLiteLog:(20 )語句中止在6:[INSERT INTO categories_table(title,imageurl,azon)VALUES(?,?,?)]數據類型mismatchE/SQLiteDatabase: 插入標題=Tânctanárimageurl = http://80.99.190.2:8080/mobil/download?id=360 azon = 71 android.database .sqlite.SQLiteDatatypeMismatchException:數據類型不匹配(編號20)
CTHandler.java:
public class CTHandler extends SQLiteOpenHelper implements CategoriesListener {
private static final int CT_VERSION = 1;
private static final String CT_NAME = "CategoriesDatabase.db";
private static final String TABLE_NAME = "categories_table";
private static final String KEY_TITLE = "title";
private static final String KEY_IMAGEURL = "imageurl";
private static final String KEY_AZON = "azon";
String CREATE_TABLE = "CREATE TABLE "+TABLE_NAME+" ("+KEY_TITLE+" TEXT,"+KEY_IMAGEURL+" TEXT,"+KEY_AZON+" TEXT)";
String DROP_TABLE = "DROP TABLE IF EXISTS "+TABLE_NAME;
public CTHandler(Context context) {
super(context, CT_NAME, null, CT_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
db.execSQL(CREATE_TABLE);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
db.execSQL(DROP_TABLE);
onCreate(db);
}
@Override
public void addCategories(CategoriesItem citem) {
SQLiteDatabase db = this.getWritableDatabase();
try{
ContentValues values = new ContentValues();
values.put(KEY_TITLE, citem.getTitle());
values.put(KEY_IMAGEURL,citem.getImageurl());
values.put(KEY_AZON,citem.getAzon());
db.insert(TABLE_NAME, null, values);
db.close();
}catch (Exception e){
Log.e("problem",e+"");
}
}
@Override
public ArrayList<CategoriesItem> getAllCategories() {
SQLiteDatabase db = this.getReadableDatabase();
ArrayList<CategoriesItem> categoriesList = null;
try{
categoriesList = new ArrayList<CategoriesItem>();
String QUERY = "SELECT * FROM "+TABLE_NAME;
Cursor cursor = db.rawQuery(QUERY, null);
if(!cursor.isLast())
{
while (cursor.moveToNext())
{
CategoriesItem ci = new CategoriesItem();
ci.setTitle(cursor.getString(0));
ci.setImageurl(cursor.getString(1));
ci.setAzon(cursor.getString(2));
categoriesList.add(ci);
}
}
db.close();
}catch (Exception e){
Log.e("error",e+"");
}
return categoriesList;
}
@Override
public int getCategoriresCount() {
int num = 0;
SQLiteDatabase db = this.getReadableDatabase();
try{
String QUERY = "SELECT * FROM "+TABLE_NAME;
Cursor cursor = db.rawQuery(QUERY, null);
num = cursor.getCount();
db.close();
return num;
}catch (Exception e){
Log.e("error",e+"");
}
return 0;
}
}
我曾嘗試使用BOLB
和INTEGER PRIMARY KEY
爲IMAGEURL沒有成功。
這是從數組一個JSON對象:
"channel":[{"title":"MENYASSZONYI RUHA","imageurl":"http://80.99.190.2:8080/mobil/download?id=350","azon":53},
這是想什麼,我救,我也想了圖像的URL將保存爲String
。我不喜歡使用Bitmaps和byte []我只想保存它就像圖像的名稱。如果有人有想法如何做,請回復。
在'CTHandler'類,你正在使azon成爲'Text'類型,但在插入時傳遞整數。請確保你傳遞字符串到該字段。 –
我應該使用'INTEGER PRIMARY KEY'作爲azon嗎?我將azon保存爲一個String,當我使用'citem.getAzon()'時,它返回一個String。 –
在添加時,您在數據庫中使用的是Azon。 –