我收到此錯誤 注意:未定義的索引:pharmacy.Name在第17行的C:\ xampp \ htdocs \ RAU \ courses.php中注意:未定義索引:delivery.Phone in C: \ XAMPP \ htdocs中\ RAU \ courses.php第19行說明:未定義指數:delivery.Address在C:\ XAMPP \ htdocs中\ RAU \ courses.php第21行如何修復未定義的變量
<link rel="stylesheet" href="style1.css">
<?php
$servername = "localhost";
$userrname = "root";
$password = "";
$dbname = "bless";
$conn = new mysqli($servername, $userrname, $password ,$dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sqlq="SELECT pharmacy.name,delivery.phone,delivery.address FROM delivery INNER JOIN pharmacy ON delivery.Pharmacy_id = pharmacy._id";
$rslt=$conn->query($sqlq) ;
$roww = $rslt->fetch_assoc();
echo "<br>";
echo "<br>";
echo "<td>" . $roww['pharmacy.name'] ;
echo "<br>";
echo"<td>". $roww['delivery.phone'];
echo "<br>";
echo"<td>". $roww['delivery.address'];
echo "<br>";
?>
'$ roww [ 'pharmacy.name']'應該是'$ roww [ '名']' –
非常感謝它的工作 –