如何從C＃中的字符串中提取多個子字符串匹配？

Question

我有一個字符串包含具有相似圖案標記的內容象下面這樣：

This is a <ss type="">(example)</ss> string which <ss type="">(contains)</ss> tagged contents. 

預期結果是：

This is a <ss type="example">(example)</ss> string which <ss type="contains">(contains)</ss> tagged contents. 

我試圖通過RegularExpression提取的標籤的內容列表，並已提取的標記文本列表，並將標記文本放在雙引號中作爲值type，並將新字符串替換爲舊字符串。

但問題是，因爲Regex.Replace();是繼同Regex模式，它取代所有標籤內容與標籤內容的最後一個元素列表如下圖所示：

This is a <ss type="contains">(contains)</ss> string which <ss type="contains">(contains)</ss> tagged contents. 

我工作的代碼如下：

StringBuilder resultText= new StringBuilder(@"This is a <ss type="">(example)</ss> string which <ss type="">(contains)</ss> tagged contents."); 
string overallPattern = @"<ss\stype=""([a-zA-Z]*)"">(.*?)</ss>"; 
List<string> matchList = new List<string>(); 
List<string> contentList = new List<string>(); 
StringBuilder sb; 
Regex overallRegex = new Regex(overallPattern, RegexOptions.None); 
string resultContent = resultText.ToString(); 
foreach (Match match in overallRegex.Matches(resultContent)) 
    { 
     string matchResult = match.ToString(); 
     matchList.Add(matchResult); 
     string content = matchResult.Split('(', ')')[1]; 
     contentList.Add(content); 
    } 
for (int j = 0; j < matchList.Count; j++) 
    { 
     sb = new StringBuilder(); 
     sb.Append(matchList[j].Insert(10, string.Format(contentList[j]))); 
     resultContent = Regex.Replace(resultContent, overallPattern, sb.ToString()); 
     resultText = new StringBuilder(); 
     resultText.Append(resultContent); 
    } 

我的問題是：

如何通過命令將正確的標記文本放入雙引號中？

Answer 1

我們根據您的replace標籤內容來創建動態Regex。例如，<ss\stype="([a-zA-Z]*)">\(example\)<\/ss>將僅替換內容中具有example的一個標籤。請檢查這一點，它會根據你的描述工作。

代碼：以上代碼的

//StringBuilder resultText = new StringBuilder(@"This is a <ss type="""">(example)</ss> string which <ss type="""">(contains)</ss> tagged contents."); 
//You have to use """" instead on "" in this line 
StringBuilder resultText = new StringBuilder(@"This is a <ss type="""">(example)</ss> string which <ss type="""">(contains)</ss> tagged contents."); 
string overallPattern = @"<ss\stype=""([a-zA-Z]*)"">(.*?)</ss>"; 
List<string> matchList = new List<string>(); 
List<string> contentList = new List<string>(); 
StringBuilder sb; 
Regex overallRegex = new Regex(overallPattern, RegexOptions.None); 
string resultContent = resultText.ToString(); 
foreach (Match match in overallRegex.Matches(resultContent)) 
{ 
    string matchResult = match.ToString(); 
    matchList.Add(matchResult); 
    string content = matchResult.Split('(', ')')[1]; 
    contentList.Add(content); 
} 
for (int j = 0; j < matchList.Count; j++) 
{ 
    //Dynamic Regex based on tag content for replace 
    overallPattern = @"<ss\stype=""([a-zA-Z]*)"">\("+ contentList[j] + "\\)</ss>"; 
    sb = new StringBuilder(); 
    sb.Append(matchList[j].Insert(10, string.Format(contentList[j]))); 
    resultContent = Regex.Replace(resultContent, overallPattern, sb.ToString()); 
    resultText = new StringBuilder(); 
    resultText.Append(resultContent); 
} 

輸出：

This is a <ss type="example">(example)</ss> string which <ss type="contains">(contains)</ss> tagged contents.

Answer 2

您只需要更換

resultContent = Regex.Replace(resultContent, overallPattern, sb.ToString()); 

通過這樣的：

resultContent = resultContent.Replace(matchList[j], sb.ToString());