移動後效果動畫完成後,TextView的定位回到原來的位置,然後旋轉。
預期的效果:
TextView的向下移動屏幕,然後在它的位置旋轉永遠
XML佈局
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/rootLayout"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
android:paddingBottom="@dimen/activity_vertical_margin"
android:gravity="center_horizontal"
tools:context=".ActivityMain">
<TextView
android:id="@+id/tv_hello"
android:text="@string/hello_world"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textStyle="bold"
android:textSize="20sp"/>
</RelativeLayout>
move.XML:
<?xml version="1.0" encoding="utf-8"?>
<set
xmlns:android="http://schemas.android.com/apk/res/android"
android:fillAfter="true"
android:interpolator="@android:anim/accelerate_interpolator">
<!-- move down -->
<translate
android:duration="800"
android:fillAfter="true"
android:fromYDelta="0%p"
android:startOffset="0"
android:toYDelta="70%p" />
</set>
個
rotate.XML:
<?xml version="1.0" encoding="utf-8"?>
<set
xmlns:android="http://schemas.android.com/apk/res/android"
android:fillBefore="true"
android:fillAfter="true"
android:interpolator="@android:anim/linear_interpolator">
<!-- infinite rotate -->
<rotate
android:fromDegrees="0"
android:toDegrees="360"
android:pivotX="50%"
android:pivotY="50%"
android:repeatCount="infinite"
android:duration="1200" />
</set>
Java代碼:
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.view.Menu;
import android.view.MenuItem;
import android.view.animation.Animation;
import android.view.animation.AnimationUtils;
import android.widget.TextView;
public class ActivityMain extends AppCompatActivity {
private TextView mTextView;
private Animation mAnimationMove;
private Animation mAnimationRotate;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mTextView = (TextView) findViewById(R.id.tv_hello);
mAnimationMove = AnimationUtils.loadAnimation(ActivityMain.this, R.anim.move);
mAnimationRotate = AnimationUtils.loadAnimation(ActivityMain.this, R.anim.rotate);
mAnimationMove.setAnimationListener(new Animation.AnimationListener() {
@Override
public void onAnimationStart(Animation animation) {
}
@Override
public void onAnimationEnd(Animation animation) {
mTextView.startAnimation(mAnimationRotate);
}
@Override
public void onAnimationRepeat(Animation animation) {
}
});
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
int id = item.getItemId();
if (id == R.id.action_settings) {
mTextView.startAnimation(mAnimationMove);
return true;
}
return super.onOptionsItemSelected(item);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_activity_main, menu);
return true;
}
}
如何才能做到這一點? 令人難以置信的是,看似簡單的事實際上相當困難!
你出兩個動畫到同一個XML /可設定,但有第二動畫有一個開始偏移第一動畫的長度是多少? –
不,這是不可能的,因爲如果我先移動它,然後以相同的XML旋轉,那麼旋轉的關鍵將是*原始*起始位置。這是完全不可取的。 –