打印奇怪值的特殊字符和數字字符

Question

我正在將字符傳遞到字符串中並使用函數混淆字符串中的字母，但是從主頂部的數組中抓取的字符正在作爲符號的重音符號打印並且數字的％符號，但是字母不受影響。幫助表示讚賞:)

#include <iostream> 
#include <string> 

using namespace std; 

void scrambleString(string str) 
{ 
    int x = str.length(); 
    for (int y = x; y > 0; y--) 
    { 
     int pos = rand() % x; 
     char tmp = str[y - 1]; 
     str[y - 1] = str[pos]; 
     str[pos] = tmp; 
    } 
    cout << str; 
} 

int main() 
{ 
    // Arrays for RNG to work with // 
    char letters[] = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 
     'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 
     's', 't', 'u', 'v', 'w', 'x', 'y', 'z' }; 

    char symbols[] = { '!', '£', '$', '%', '&', '*', '@', '~' }; 

    char numbers[] = { '1', '2', '3', '4', '5', '6', '7', '8', '9' }; 

    // Other Variables // 
    int letterIn; 
    int specialIn; 
    int numberIn; 
    string randomPass; 
    string holdString; 

    cout << "No of Letters: "; 
    cin >> letterIn; 
    cout << "No of Special char: "; 
    cin >> specialIn; 
    cout << "No of Numbers: "; 
    cin >> numberIn; 

    // Letters 
    for (int i = 0; i < letterIn; i++) 
    { 
     int RNG = rand() % 26; 
     char holdChar = letters[RNG]; 
     // Convert to String 
     holdString.insert(i, 1, holdChar); 

    } 
    // Symbols 
    for (int i = 0; i < specialIn; i++) 
    { 
     int RNG = rand() % 8; 
     char holdChar = symbols[RNG]; 
     // Convert to String 
     holdString.insert(letterIn, 1, holdChar); 
    } 
    // Numbers 
    for (int i = 0; i < numberIn; i++) 
    { 
     int RNG = rand() % 8; 
     char holdChar = symbols[RNG]; 
     // Convert to String 
     holdString.insert(letterIn+specialIn, 1, holdChar); 
    } 
    cout << holdString << endl; 
    scrambleString(holdString); 
} 

Answer 1

你的錯誤是在最後的for循環末

// Numbers 
    for (int i = 0; i < numberIn; i++) 
    { 

明確這一行：

 char holdChar = symbols[RNG]; 

這應該是char holdChar = numbers[RNG];

也可作爲在評論'£'中指出需要從你的代碼中刪除，因爲它不是一個ASCII字符ACTER。