如何從重載的構造傳遞基礎參數到派生類

Question

主要

static void Main(string[] args) 
    { 
     string name = "Me"; 
     int height = 130; 
     double weight = 65.5; 
     BMI patient1 = new BMI(); 
     BMI patient2 = new BMI(name,height,weight); 

     Console.WriteLine(patient2.Get_height.ToString() + Environment.NewLine + patient1.Get_height.ToString()); 
     Console.ReadLine(); 
    } 

基類

class BMI 
{ 
    //memberVariables 
    private string newName; 
    private int newHeight; 
    private double newWeight; 

    //default constructor 
    public BMI(){} 

    //overloaded constructor 
    public BMI(string name, int height, double weight) 
    { 
     newName = name; 
     newHeight = height; 
     newWeight = weight; 
    } 

    //poperties 
    public string Get_Name 
    { 
     get { return newName; } 
     set { newName = value;} 
    } 

    public int Get_height 
    { 
     get { return newHeight; } 
     set { newHeight = value; } 
    } 

    public double Get_weight 
    { 
     get { return newWeight; } 
     set { newWeight = value; } 
    } 
} 

派生類

class Health : BMI 
{ 
    private int newSize; 
    public Health(int Size):base() 
    { 
     newSize = Size; 
    } 
} 

如何傳遞在基座參數從BMI基類中的重載構造函數轉換爲派生類？ 任何時候我嘗試將它們傳遞到基本參數，我得到無效的表達式錯誤。 或者我只需要將它們傳遞給主對象中的Health對象？ 如

class Health : BMI 
{ 
    private int newSize; 

    public Health(int Size, string Name, int Height, double Weight) 
    { 
     newSize = Size; 
     base.Get_Name = Name 
     base.Get_weight = Weight; 
     base.Get_height = Height; 
    } 
} 

Answer 1

構造函數是不可繼承的，所以是的，你需要創建基類一個新的構造，但你可以叫用正確的參數基本構造：

public Health(int size, string name, int height, double weight) 
    : base(name, height, weight) 
{ 
    newSize = size; 
} 

Answer 2

篩選：

class Health : BMI 
{ 
    private int newSize; 

    public Health(int Size, string Name, int Height, double Weight) 
     : base(Name, Height, Weight) 
    { 
     newSize = Size; 
    } 
} 

Answer 3

你爲什麼不能調用基類的構造函數傳遞參數一樣

public Health(int Size, string Name, int Height, double Weight) 
    : base(Name, Height, Weight) 
{ 
    newSize = Size; 
}