如何立即執行承諾

需要執行承諾的幫助。代碼：如何立即執行承諾

it('[TEST-1] Log in with invalid credentials-wrong email', function() { 
    //LogIn 
    browser.logger.info("[ENTRY] - Username: " + browser.params.Adenity.loginInfo[2].username); 
    element(by.id('js-input-email')).sendKeys(browser.params.Adenity.loginInfo[2].username); 
    expect(element(by.id('js-input-email')).getAttribute('value')).toEqual(browser.params.Adenity.loginInfo[2].username); 
    element(by.id('js-input-email')).getAttribute('value').then(function(pom) { 
     if (pom == browser.params.Adenity.loginInfo[2].username) 
      browser.logger.info("Username populated succesfully"); 
     else 
      browser.logger.info("Username not populated succesfully"); 
    }); 
    browser.logger.info("[ENTRY] - Password: " + browser.params.Adenity.loginInfo[2].password); 
    element(by.id('js-input-password')).sendKeys(browser.params.Adenity.loginInfo[2].password); 
    expect(element(by.id('js-input-password')).getAttribute('value')).toEqual(browser.params.Adenity.loginInfo[2].password); 
    element(by.id('js-input-password')).getAttribute('value').then(function(pom) { 
     if (pom == browser.params.Adenity.loginInfo[2].password) 
      browser.logger.info("Password populated succesfully"); 
     else 
      browser.logger.info("Password not populated succesfully"); 
    }); 
});

實際結果：

[INFO] protractorLog4js - [ENTRY] - Username: [email protected] 
[INFO] protractorLog4js - [ENTRY] - Password: Test1234 
[INFO] protractorLog4js - Username populated succesfully 
[INFO] protractorLog4js - Password populated succesfully

我想要的結果：

[INFO] protractorLog4js - [ENTRY] - Username: [email protected] 
[INFO] protractorLog4js - Username populated succesfully 
[INFO] protractorLog4js - [ENTRY] - Password: Test1234 
[INFO] protractorLog4js - Password populated succesfully

我不知道我應該如何解決這個問題，所以任何幫助表示讚賞。

來源

2017-09-28 asalosevic1

['.resolve']（HTTPS ：//developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/resolve）？ –

你**不能讓異步代碼神奇地同步。查看[這個問題]的答案（http://stackoverflow.com/questions/14220321/how-do-i-return-the-response-from-an-asynchronous-call），它討論了一系列異步操作。就你而言，你正在尋找一個關於串聯（不平行）的答案。您還需要了解您的測試框架如何處理異步測試。 –

就像Javascript一樣令人驚歎，它不能做時間旅行：p –

的SendKeys也返回一個承諾，從而保證事情發生的順序您希望您的代碼必須看起來更像：

element(by.id('js-input-email')).sendKeys(browser.params.Adenity.loginInfo[2].username).then(function() { 
    return element(by.id('js-input-email')).getAttribute('value'); 
}).then(function(pom) { 
    if (pom == browser.params.Adenity.loginInfo[2].username) 
     browser.logger.info("Username populated succesfully"); 
    else 
     browser.logger.info("Username not populated succesfully"); 

    browser.logger.info("[ENTRY] - Password: " + browser.params.Adenity.loginInfo[2].password); 
    return element(by.id('js-input-password')).sendKeys(browser.params.Adenity.loginInfo[2].password) 
}).then(function() { 
    expect(element(by.id('js-input-password')).getAttribute('value')).toEqual(browser.params.Adenity.loginInfo[2].password); 
    return element(by.id('js-input-password')).getAttribute('value') 
}).then(function(pom){ 
    if (pom == browser.params.Adenity.loginInfo[2].password) 
     browser.logger.info("Password populated succesfully"); 
    else 
     browser.logger.info("Password not populated succesfully"); 
});

看到的 - https://javascript.info/promise-chaining

來源

2017-09-28 10:59:46

如何立即執行承諾

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