需要MySQL查詢以提供更多可讀結果

我有一個MySQL數據庫，其中包含表'people'，'questions'和'answers'。我有這個疑問：需要MySQL查詢以提供更多可讀結果

SELECT CONCAT(people.firstName, ' ', people.lastName) as Name, people.emailAddress, questions.fruit, answers.fruitID, answers.info, answers.dateLogged, questions.fruitID, questions.questionairID, questions.person 
From answers 
Join questions ON answers.fruitID= questions.fruitID 
JOIN people ON questions.person= people.personID 
WHERE questions.questionairID= '24' 
ORDER BY people.personID

將會產生這樣的結果：

+------------------+--------------------+--------+-----------------+-------------------+-------------------+-----------------+---------------+--------+ 
|  Name  | emailAddress | fruit | fruitInstanceID |  info  | dateLogged  | fruitInstanceID | questionairID | person | 
+------------------+--------------------+--------+-----------------+-------------------+-------------------+-----------------+---------------+--------+ 
| Harry Potter  | [email protected] | apple |    107 | NULL    | 05/26/17 07:23 PM |    107 |   24 |  6 | 
| Ron Weasley  | [email protected] | apple |    113 | NULL    | 05/26/17 06:30 PM |    113 |   24 |  8 | 
| Hermione Granger | [email protected] | apple |    116 | NULL    | 05/26/17 06:29 PM |    116 |   24 |  9 | 
| Hermione Granger | [email protected] | orange |    114 | NULL    | 05/26/17 06:36 PM |    114 |   24 |  9 | 
| Hermione Granger | [email protected] | apple |    116 | NULL    | 05/26/17 08:28 PM |    116 |   24 |  9 | 
| Hermione Granger | [email protected] | orange |    114 | NULL    | 05/26/17 08:28 PM |    114 |   24 |  9 | 
| Hermione Granger | [email protected] | orange |    114 | some extra info | 05/26/17 08:29 PM |    114 |   24 |  9 | 
| Hermione Granger | [email protected] | orange |    114 | more extra info | 05/26/17 08:29 PM |    114 |   24 |  9 | 
| Hermione Granger | [email protected] | orange |    114 | NULL    | 05/26/17 08:31 PM |    114 |   24 |  9 | 
| Severus Snape | [email protected] | apple |    119 | NULL    | 05/26/17 06:37 PM |    119 |   24 |  10 | 
| Severus Snape | [email protected] | orange |    117 | NULL    | 05/26/17 06:46 PM |    117 |   24 |  10 | 
| Severus Snape | [email protected] | orange |    117 | user entered info | 05/26/17 06:46 PM |    117 |   24 |  10 | 
| Severus Snape | [email protected] | orange |    117 | more user info | 05/26/17 06:46 PM |    117 |   24 |  10 | 
| Severus Snape | [email protected] | orange |    117 | info again  | 05/26/17 06:46 PM |    117 |   24 |  10 | 
| Remus Lupin  | [email protected] | apple |    122 | NULL    | 05/26/17 06:29 PM |    122 |   24 |  11 | 
| Viktor Krum  | [email protected] | apple |    125 | NULL    | 05/26/17 06:30 PM |    125 |   24 |  12 | 
| Molly Weasley | [email protected] | apple |    128 | NULL    | 05/26/17 06:36 PM |    128 |   24 |  13 | 
| Molly Weasley | [email protected] | apple |    128 | NULL    | 05/26/17 07:22 PM |    128 |   24 |  13 | 
| Molly Weasley | [email protected] | orange |    126 | NULL    | 05/26/17 07:37 PM |    126 |   24 |  13 | 
| Molly Weasley | [email protected] | orange |    126 | NULL    | 05/26/17 07:37 PM |    126 |   24 |  13 | 
| Oliver Wood  | [email protected] | apple |    131 | NULL    | 05/26/17 06:33 PM |    131 |   24 |  14 | 
| Oliver Wood  | [email protected] | banana |    133 | NULL    | 05/26/17 06:33 PM |    133 |   24 |  14 | 
+------------------+--------------------+--------+-----------------+-------------------+-------------------+-----------------+---------------+--------+

這是偉大的。它具有我需要的所有信息（以及更多），但更具可讀性的格式會很好。我可以使用什麼樣的查詢，讓我更多的東西是這樣的：

+------------------+--------------------+-------+--------+--------+ 
|  Name  | emailAddress | Apple | Orange | Banana | 
+------------------+--------------------+-------+--------+--------+ 
| Harry Potter  | [email protected] | YES |  |  | 
| Ron Weasley  | [email protected] | YES |  |  | 
| Hermione Granger | [email protected] | YES | YES |  | 
| Severus Snape | [email protected] | YES | YES |  | 
| Remus Lupin  | [email protected] | YES |  |  | 
| Viktor Krum  | [email protected] | YES |  |  | 
| Molly Weasley | [email protected] | YES | YES |  | 
| Oliver Wood  | [email protected] | YES |  | YES | 
+------------------+--------------------+-------+--------+--------+

或紅利，也算次數的水果：

+------------------+--------------------+---------+---------+--------+ 
|  Name  | emailAddress | Apple | Orange | Banana | 
+------------------+--------------------+---------+---------+--------+ 
| Harry Potter  | [email protected] | YES  |   |  | 
| Ron Weasley  | [email protected] | YES  |   |  | 
| Hermione Granger | [email protected] | YES (2) | YES (5) |  | 
| Severus Snape | [email protected] | YES  | YES (4) |  | 
| Remus Lupin  | [email protected] | YES  |   |  | 
| Viktor Krum  | [email protected] | YES  |   |  | 
| Molly Weasley | [email protected] | YES (2) | YES (2) |  | 
| Oliver Wood  | [email protected] | YES  |   | YES | 
+------------------+--------------------+---------+---------+--------+

來源

2017-05-27 Just a Sec User

這應該第一種情況下工作 -

SELECT CONCAT(people.firstName, ' ', people.lastName) as Name, 
people.emailAddress, 
(CASE questions.fruit 
    WHEN 'apple' THEN 'YES' 
    ELSE '' 
END) as Apple, 
(CASE questions.fruit 
    WHEN 'orange' THEN 'YES' 
    ELSE '' 
END) as Orange, 
(CASE questions.fruit 
    WHEN 'banana' THEN 'YES' 
    ELSE '' 
END) as Banana 
From answers 
Join questions ON answers.attackID = campaign.attackID 
JOIN employees ON campaign.employee = employees.employeeID 
WHERE campaign.campaignID = '24' 
ORDER BY employees.employeeID

不確定在第二種情況下計數如何工作。但我認爲它會在employeeid上分組。

UPDATE

因爲我不認爲有必要對文本第二種情況「YES」，水果的數量應足以決定。嘗試此計數 -

SELECT CONCAT(people.firstName, ' ', people.lastName) as Name, 
people.emailAddress, 
SUM(CASE questions.fruit 
    WHEN 'apple' THEN 1 
    ELSE 0 
END) as 'AppleCount', 
SUM(CASE questions.fruit 
    WHEN 'orange' THEN 1 
    ELSE 0 
END) as 'OrangeCount', 
(CASE questions.fruit 
    WHEN 'banana' THEN 1 
    ELSE 0 
END) as 'BananaCount' 
From answers 
Join questions ON answers.attackID = campaign.attackID 
JOIN employees ON campaign.employee = employees.employeeID 
WHERE campaign.campaignID = '24' 
GROUP BY employees.employeeID 
ORDER BY employees.employeeID

來源

2017-05-27 17:20:37

我將在幾分鐘後重試。我忘記更新查詢中的一些字段以查看我的示例。這就是爲什麼你看到了employeeid而不是personid，這在問題中更有意義。。 –

這工作得很好！第一個結果列出了所有人的記錄（所以我爲Hermione和其他人記錄了幾行），但我認爲我可以通過一個組來解決這個問題。第二個工作完美。謝謝！ –

太棒了！ Enjoy ... –

需要MySQL查詢以提供更多可讀結果

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