2017-08-07 77 views
0

我有MySQL數據庫與表名'用戶'。我想根據「身份證號碼」搜索數據。例如:如果我想搜索ID爲14的ID,它應顯示ID = 14的所有記錄(姓,名,性別,國家,電子郵件等)。搜索並顯示結果與數據庫

這裏是我的代碼:

data.php

<?php 
require_once ('connect.php'); 
if(isset($_POST['done'])) 
{ 
    $FirstName = $_POST['firstname']; 
    $LastName = $_POST['lastname']; 
    $DateofBirth =$_POST['dateofbirth']; 
    $Email = $_POST['email']; 
    $Gender = $_POST['gender']; 
    $Country = $_POST['country']; 
    $Website = $_POST['website']; 
    $Bio = $_POST['bio']; 

$CreateSql="INSERT INTO `user` (`First Name`, `Last Name`, `Gender`,`Date of Birth`, `Country`, `Email`, `Website`, `Bio`,`Created Date`) 
     VALUES ('$FirstName', '$LastName', '$Gender','$DateofBirth', '$Country', '$Email', '$Website', '$Bio',NOW())"; 
$insert = mysqli_query($connection,$CreateSql) or die(mysqli_error($connection)); 
if($insert) 
    { 
     echo 'Data Inserted'; 
    }else 
    { 
     echo 'mysqli_error()'; 
    } 
} 

//header ("refresh:2; url=index.php"); 

?> 

<html> 
    <head> 
    <meta name="viewport" content="width=device-width, initial-scale=1"> 
     <title>View Data</title> 
     <link href="css/bootstrap.min.css" rel="stylesheet"> 

    <!-- HTML5 shim and Respond.js for IE8 support of HTML5 elements and media queries --> 
    <!-- WARNING: Respond.js doesn't work if you view the page via file:// --> 
    <!--[if lt IE 9]> 
     <script src="https://oss.maxcdn.com/html5shiv/3.7.3/html5shiv.min.js"></script> 
     <script src="https://oss.maxcdn.com/respond/1.4.2/respond.min.js"></script> 
    <![endif]--> 
    </head> 
    <body> 
     <table width="1200" class="table-bordered" border="1" cellpadding="1" cellspacing="5"> 
     <tr> 
      <th><center>ID</center></th> 
      <th><center>First Name</center></th> 
      <th><center>Last Name</center></th> 
      <th><center>Gender</center></th> 
      <th><center>Date of Birth</center></th> 
      <th><center>Registration Date</center></th> 
      <th><center>Action</center></th> 
     </tr> 

<?php 
$select = "SELECT * FROM `user` "; 
$record = mysqli_query($connection,$select); 
while($data = mysqli_fetch_array($record)) 
{ 
?> 
    <tr> 
    <td><center><?php echo $data['ID']; ?></center></center></td> 
    <td><center><?php echo $data['First Name']; ?></center></td> 
    <td><center><?php echo $data['Last Name']; ?></center></td> 
    <td><center><?php echo $data['Gender']; ?></center></td> 
    <td><center><?php echo $data['Date of Birth']; ?></center></td> 
    <td><center><?php echo $data['Created Date']; ?></center></td> 
    <td><center><a href="view.php?ID=<?php echo $data['ID']; ?>">View</a> 
      <a href="search.php?ID=<?php echo $data['ID']; ?>">Search</a> 
     <a href="edit.php?ID=<?php echo $data['ID']; ?>"><span class="glyphicon glyphicon-edit" aria-hidden="true">Edit</span></a> 
     <a href="delete.php?ID=<?php echo $data['ID']; ?>"><span class="glyphicon glyphicon-remove" aria-hidden="true">Delete</span></a></center></td> 
    <tr> 
<?php 
} 
?> 
    </table> 
    <br> 
    <div class="row"> 
    <div class="col-md-12"> 
     <center><a href="index.php"><input type="submit" name="done" class="btn btn-success btn-send" value="Add User"></a></center> 

      <a href="search.php?ID=<?php echo $data['ID']; ?>"><input type="submit" name="search" class="btn btn-success btn-send" value="Search ID"></a> 
      <input type="text" name="search" value="<?php echo $data['ID']; ?>" 

的search.php

<?php 
require_once ('connect.php'); 
$ID = $_GET['ID']; 
?> 
<html> 
    <head> 
     <meta name="viewport" content="width=device-width, initial-scale=1"> 
     <title>View Data</title> 
     <link href="css/bootstrap.min.css" rel="stylesheet"> 

     <!-- HTML5 shim and Respond.js for IE8 support of HTML5 elements and media queries --> 
     <!-- WARNING: Respond.js doesn't work if you view the page via file:// --> 
     <!--[if lt IE 9]> 
     <script src="https://oss.maxcdn.com/html5shiv/3.7.3/html5shiv.min.js"></script> 
     <script src="https://oss.maxcdn.com/respond/1.4.2/respond.min.js"></script> 
     <![endif]--> 
    </head> 
     <body> 
     <table width="1200" border="2" cellpadding="1" cellspacing="1"> 
      <tr> 
      <th><center>ID</center></th> 
      <th><center>First Name</center></th> 
      <th><center>Last Name</center></th> 
      <th><center>Email</center></th> 
      <th><center>Gender</center></th> 
      <th><center>Date of Birth</center></th> 
      <th><center>Country</center></th> 
      <th><center>Website</center></th> 
      <th><center>Bio </center></th> 
      <th><center>Registration Date</center></th> 
      </tr> 

<?php 
$search = mysqli_query($connection,"SELECT * FROM `user` WHERE `ID` = '$ID' "); 
while($data= mysqli_fetch_array($search)) 
{ 
?> 
    <tr> 
    <td><center><?php echo $data['ID']; ?></center></center></td> 
    <td><center><?php echo $data['First Name']; ?></center></td> 
    <td><center><?php echo $data['Last Name']; ?></center></td> 
    <td><center><?php echo $data['Email']; ?></center></td> 
    <td><center><?php echo $data['Gender']; ?></center></td> 
    <td><center><?php echo $data['Date of Birth']; ?></center></td> 
    <td><center><?php echo $data['Country']; ?></center></td> 
    <td><center><?php echo $data['Website']; ?></center></td> 
    <td><center><?php echo $data['Bio']; ?></center></td> 
    <td><center><?php echo $data['Created Date']; ?></center></td> 
    <tr> 
<?php 

if($search) 
     { 
     echo 'Record Found'; 
     }else 
     { 
     echo 'mysqli_error()'; 
     } 
} 
?> 
</table> 
</body> 
</html> 

與上面的代碼我得到這樣的輸出:它顯示選定沒有記錄ID。 enter image description here

+3

[小博](http://bobby-tables.com/)說** [你的腳本是SQL注入攻擊的風險](http://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php)**。瞭解[Prepared Statements](http:// en .wikipedia.org/wiki/Prepared_statement)[MySQLi](http://php.net/manual/en/mysqli.quickstart.prepared-statements.php)。甚至** [轉義字符串](http:// stackoverflow.com/questions/5741187/sql-injection-that-gets-around-mysql-real-escape-string)**不安全! – GrumpyCrouton

+0

一些明智的代碼縮進將是一個好主意。 它可以幫助我們閱讀代碼,更重要的是它可以幫助您調試代碼**。 [快速瀏覽編碼標準](http://www.php-fig.org/psr/psr-2/)爲您帶來的好處。 您可能會被要求在幾周/幾個月內修改此代碼,最後您會感謝我。 – GrumpyCrouton

回答

0
  • 調試與error_reporting(E_ALL);你的代碼。它可以幫助你找到錯誤 。把它放在你的search.php上面
  • echo你的SQL語句檢查它是否有效。您也可以在phpadmin或任何您使用的地方複製並運行它。

    回聲$ SQL =「SELECT * FROM ...

PHP error_reporting