C＃ - 如何阻止GUI或事件

Question

我想創建一個非常簡單的遊戲Simon與WiiMote，使用WPF。我堅持的是如何使它基於轉向，程序阻塞，直到GUI完成顯示一個序列。

這裏是我迄今（主要是基於一個答案在這裏：WPF - sequential animation simple example）：代碼

public partial class Window1 : Window 
{ 

    public enum SimonSquare { BLUE = 1, GREEN = 3, RED = 5, YELLOW = 7 }; 

    List<int> _correctSequence; 
    int _currentLevel = 1; 
    Random random = new Random(); 
    Wiimote _wiiMote; 
    List<int> _squaresEntered; 
    private IEnumerator<Action> _actions; 
    Rectangle blueRect; 
    Rectangle redRect; 
    Rectangle greenRect; 
    Rectangle yellowRect; 

    AutoResetEvent autoEvent; 

    public Window1() 
    { 
     InitializeComponent(); 
     blueRect = new Rectangle() { Fill = 
      System.Windows.Media.Brushes.Blue, Name = "Blue"}; 
     redRect = new Rectangle() { Fill = 
      System.Windows.Media.Brushes.Red, Name = "Red" }; 
     greenRect = new Rectangle() { Fill = 
      System.Windows.Media.Brushes.Green, Name = "Green" }; 
     yellowRect = new Rectangle() { Fill = 
      System.Windows.Media.Brushes.Yellow, Name = "Yellow" }; 

     UniformGrid1.Children.Add(new Rectangle() { Fill = 
      System.Windows.Media.Brushes.LightGray }); 
     UniformGrid1.Children.Add(blueRect); 
     UniformGrid1.Children.Add(new Rectangle() { Fill = 
      System.Windows.Media.Brushes.LightGray }); 
     UniformGrid1.Children.Add(redRect); 
     UniformGrid1.Children.Add(new Rectangle() { Fill = 
      System.Windows.Media.Brushes.LightGray }); 
     UniformGrid1.Children.Add(greenRect); 
     UniformGrid1.Children.Add(new Rectangle() { Fill = 
      System.Windows.Media.Brushes.LightGray }); 
     UniformGrid1.Children.Add(yellowRect); 
     UniformGrid1.Children.Add(new Rectangle() { Fill = 
      System.Windows.Media.Brushes.LightGray }); 
     //connectWiiRemote(); 

    } 

    private void Window_Loaded(object sender, RoutedEventArgs e) 
    { 
     _actions = AnimationSequence().GetEnumerator(); 
     autoEvent = new AutoResetEvent(false); 
     Thread thread = new Thread(RunNextAction); 
     thread.Start(); 
     autoEvent.WaitOne(); // need to block here somehow! 
     int x = 5; 
    } 

    IEnumerable<Action> AnimationSequence() 
    { 
     getSequence(); 
     foreach(int square in _correctSequence) 
     { 
      if(square == (int) SimonSquare.BLUE) 
       yield return() => animateCell(blueRect, Colors.Blue); 
      else if(square == (int) SimonSquare.RED) 
       yield return() => animateCell(redRect, Colors.Red); 
      else if (square == (int)SimonSquare.GREEN) 
       yield return() => animateCell(greenRect, Colors.Green); 
      else if (square == (int)SimonSquare.YELLOW) 
       yield return() => animateCell(yellowRect, Colors.Yellow); 
     } 
    } 

    private void animateCell(Rectangle rectangle, Color fromColor) 
    { 
     this.Dispatcher.BeginInvoke(new Action(delegate 
     { 
      Color toColor = Colors.White; 
      ColorAnimation ani = new ColorAnimation(toColor, 
       new Duration(TimeSpan.FromMilliseconds(300))); 
      ani.AutoReverse = true; 
      SolidColorBrush newBrush = new SolidColorBrush(fromColor); 
      ani.BeginTime = TimeSpan.FromSeconds(2); 
      rectangle.Fill = newBrush; 
      ani.Completed += (s, e) => RunNextAction(); 
      newBrush.BeginAnimation(SolidColorBrush.ColorProperty, ani); 

     })); 
    } 

    private void RunNextAction() 
    { 
     if (_actions.MoveNext()) 
      _actions.Current(); 
     else 
     { 
      autoEvent.Set(); 
      _currentLevel++; 
     } 
    } 

    private void getSequence() 
    { 
     _correctSequence = new List<int>(); 
     int[] values = 
      Enum.GetValues(typeof(SimonSquare)).Cast<int>().ToArray(); 
     for (int i = 0; i < _currentLevel + 2; i++) 
     { 
      _correctSequence.Add(values[random.Next(values.Length)]); 
     } 

    } 
} 

然而，因爲自動設置的了WaitOne /組無法正常工作。它目前調用RunNextAction一次，但是無限期地阻塞waitOne。我究竟做錯了什麼？

編輯： 讓我試着重述這個問題。如果我拿出線程和的AutoResetEvent，在Window_Loaded我：

private void Window_Loaded(object sender, RoutedEventArgs e) 
    { 
     _actions = AnimationSequence().GetEnumerator(); 
     RunNextAction(); // shows all of the flashing squares 
     // need to wait here until the flashing squares are all shown 
     // process player's events etc. 
    } 

當我運行上面的代碼，它會調用一次RunNextAction，這將讓自稱，直到所有的方塊都顯示（似乎就像它自己的線程一樣），但WindowLoaded方法繼續下去。在我調用RunNextAction（）之後，我需要Window_Loaded阻塞，直到RunNextAction完成。

Answer 1

您不應該在調度程序線程上調用WaitOne！

您在調度程序線程本身調用WaitOne，調度程序線程是WPF APP的主線程，如果您阻止它，任何調用Dispatcher.BeginInvoke或Invoke的調用將永遠不會調用，並且將無限期地等待。

相反，更好的方法是將您的動畫移動到另一個名爲「AnimationDialog」的窗口並將其加載爲模態對話框。

private void window_loaded(object sender, EventArgs e){ 

    AnimationDialog dialog = new AnimationDialog(); 
    dialog.Owner = this; 
    dialog.ShowDialog(); // this will wait here 

} 

在AnimationDialog窗口...

private void Window_Loaded(object sender, EventArgs e){ 
    StartAnimationThread(); 
    // dont do any wait or block here at all... 
} 

// in your end of animation call "EndAnimation()" 

private void EndAnimation(){ 
    Dispatcher.BeginInvoke()((Action)delegate(){ 
     this.DialogResult = true; 
     // this will stop this dialog and 
     // and execute the parent window's 
     // code where showdialog was called... 
    } 
    ) 
} 

Answer 2

我可能會誤解你的問題，因爲這看起來很簡單。在您的Window_Loaded事件中，刪除thread.Start();後的所有內容。添加一個名爲_ImDoneSimonizing的類級變量，並將其初始化爲false。對於接收用戶輸入的任何方法，把這個包繞着代碼：

if (_ImDoneSimonizing) 
{ 
    // do whatever 
} 

當動畫完成後，設置_ImDoneSimonizing到true。其他

兩點：

1. 非常酷，你帶回西蒙。自Twister以來的最佳遊戲。
2. 你可以使用WPF爲Wii創建遊戲嗎？先生，你震動了我的世界。

Answer 3

AutoResetEvent正在執行它設計的任務，阻塞線程執行直到調用Set（）。這可能意味着你沒有調用Set（）。也許你的迭代器沒有按你期望的方式工作（雖然沒有測試它看起來沒問題）。

你是否在其他地方調用Window_Loaded？

Answer 4

您可能能夠通過抽窗口消息隊列來解決這個問題。基本上，如果您向消息隊列發佈回調，則調用線程將會阻塞，直到呈現完成。這裏有一篇文章解釋瞭如何做到這一點：http://graemehill.ca/wpf-rendering-thread-synchronization