我想通過一個jQuery變量使用AJAX的PHP,但它似乎並沒有通過。出於測試目的,我有以下幾點:jQuery的 - 傳遞變量到PHP
JQUERY:
var runin_pickup = 1200;
// Send to our checkRuninTariff function
checkRuninTariff(runin_pickup);
`
function checkRuninTariff(runin_pickup) {
$.ajax({
// Request sent from control panel, so send to cp.request.php (which is the handler)
url: 'scripts/php/bootstrp/all.request.php',
type: 'POST',
// Build data array - look at the '$_REQUEST' parameters in the 'insert' function
data: 'fnme=runIn&field_runin_p='+runin_pickup,
dataType: 'text',
timeout: 20000,
error: function(){
alert("There was a problem...")
},
success: function(){
alert(runin_pickup+' passed successfully')
}
});
}
這被傳遞給all.request.php:
<?php
include('../../../deployment.php');
require_once('controllers/xml.controller.php');
require_once('controllers/tariff.fare.controller.php');
require_once('controllers/datagrid.controller.php');
require_once('controllers/get.bookings.php');
// Switch to determine method to call
switch ($_REQUEST['fnme']) {
case 'runIn':
header('Content-type: text/html');
echo TariffFareController::getFare($_REQUEST['field_runin_p']);
break;
case 'g_fare':
header('Content-type: text/html');
echo TariffFareController::fareRequestHandler($_REQUEST['v_sys'],$_REQUEST['j_dis'],$_REQUEST['pc_arr'],
$_REQUEST['leg_arr'],$_REQUEST['return_j'],$_REQUEST['j_date'],$_REQUEST['j_time'],
$_REQUEST['r_date'],$_REQUEST['r_time'],$_REQUEST['wait_return_j']);
break;
}
終於到了tariff.fare.controller.php:
public static function getFare($int_terminate,$fieldPickup) {
if($fieldPickup > 1100) {
$fare = 222.00;
}
else {
$fare = 111.00;
}
}
在Firebug控制檯我可以看到field_runin_p = 1200
但是,如果我做的var_dump($ fieldPickup);當它應該是1200
時,這是NULL。任何想法爲什麼這不起作用?
任何幫助將不勝感激!